Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 3, Problem 29QP
Summary Introduction
To predict: The expected
Introduction: The dominant allele masks the expression of the recessive allele. Therefore, the dominant allele is expressed in homozygous and heterozygous genotypes whereas the recessive phenotype is only expressed under homozygous condition.
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Consider the following dihybrid testcross: B/b • E/e × b/b • e/e
For the progeny from this testcross, determine the relative proportions (from 0% to 100%) of each genotype if the two genes:
a) are linked (dominant alleles in cis conformation) with no crossing over: Be/be:
be/be:
BE/be:
bE/be:
b) assort independently.
B/b; E/e:
B/b; e/e:
b/b; E/e:
b/b; e/e:
c) are linked (dominant alleles in cis conformation) and 20 map units apart. Be/be:
be/be:
BE/be:
bE/be:
In guinea pigs, the black coat (B) is dominant over the white coat (b), and straight hair (H) is dominant over curly hair (h). Using a Punnett square, complete the cross between a heterozygous black, curly-haired individual and a homozygous straight-haired, white individual. State the parent genotypes and gametes, and the F1 phenotypes and genotypes.
In the following cross, imagine that you have a female fly that has two Xs and one Y
due to a nondisjunction event in her mother's germ cells. Draw out what the
possible gametes are for both the female and the male and also a Punnett square
showing the genotypes, phenotypes, and sex of the possible flies as a result of this
cross. You do not need to provide the probabilities of each of these.
Red-eyed wi
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wt
XX Y
X Y
Meiosis
Chapter 3 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 3.4 - Why do scientists design experiments to disprove...Ch. 3.4 - Should Ockhams razor be considered an irrefutable...Ch. 3.7 - Prob. 1EGCh. 3.7 - For most cases, a p value of 0.05 is used to...Ch. 3 - Prob. 1CSCh. 3 - Prob. 2CSCh. 3 - Prob. 3CSCh. 3 - Prob. 1QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...
Ch. 3 - Prob. 4QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Prob. 6QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Prob. 14QPCh. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Prob. 17QPCh. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Variations on a Theme by Mendel A characteristic...Ch. 3 - Prob. 29QPCh. 3 - Variations on a Theme by Mendel Pea plants usually...Ch. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QP
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- In sesame plants, the one-pod condition (P) is dominant to the three-pod condition (p), and normal leaf (L) is dominant to wrinkled leaf (l). Pod type and leaf type are inherited independently. Determine the genotypes for the two parents for all possible matings producing the following offspring: 318 one-pod, normal leaf and 98 one-pod, wrinkled leaf. show your solution using punnet squarearrow_forwardIn pea plants, yellow seeds (Y) are dominant to green seeds (y) and round seeds (R) are dominant to wrinkled seeds (). The genes for seed color and seed shape are on different chromosomes. Two true-breeding parents, one with yellow round peas and the other with green wrinkled peas, are crossed to produce a hybrid (heterozygous) F₁. Two F₁ individuals are crossed to give an F2; this is depicted in the Punnett square below. Place the correct genotypes in the Punnett square and the place the correct phenotypic ratios next to their appropriate phenotype on the right. YYRR YYRr YyRR YYrr yyRR yyRr Yyrr YyRr 3/16 1/16 yyrr 9/16 3/16 1/4 E 1/2 16/16 YR ✪✪✪ Yr yR YYRR Y YyRr Yr yR YR YYRr YYRR YyRr yr YyRr yyrr yr YyRr Yyrr yyRr F2 phenotype Phenotypic ratio Aarrow_forwardIn corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants (i.e. the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male-fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Using the following color-coded circles, simulate the crosses indicated below. Put the illustrations of crosses in the spaces provided. Be sure to include in the labels the genotypes and phenotypes of the offspring in each cross. Big light green circle - male-sterile cytoplasm Big orange circle - male-fertile cytoplasm Small orange circle - FF nucleus Small half-light green-half-orange circle - Ff nucleus Small light-green circle - ff nucleusarrow_forward
- Mendel's Law of Independent Assortment states that: the members of a pair of homologous chromosemes assort independently of each other during gamete formation none of these the members of a pair of homologous chromosomes separate from each other during gamete formati different pairs of homologous chromosomes assort independently of each other during gamete formation different pairs of homologous chromosomes separate from each other during gamete formationarrow_forwardIn corn, purple kernels (P) are dominant over yellow kernels (p) and starchy kernels (Su) are dominant over sugary kernels (su). A corn plant grown from a purple and starchy kernel is crossed with a plant grown from a yellow and sugary kernel, and the following progeny (kernels) are produced: Phenotype Number purple, starchy 150 purple, sugary 142 yellow, starchy 161 yellow, sugary 115 Formulate a hypothesis about the genotypes of the parents and offspring in this cross. Perform a chi-square goodness-of-fit test comparing the observed progeny with the numbers expected based on your genetic hypothesis. What conclusion can you draw based on the results of your chi-square test? Can you suggest an explanation for the observed results?arrow_forwardtype P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSarrow_forward
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