University Physics Volume 2
18th Edition
ISBN: 9781938168161
Author: OpenStax
Publisher: OpenStax
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Textbook Question
Chapter 3, Problem 17CQ
There is no change in the internal of an ideal gas undergoing an isothermal process since the internal energy depends only on the temperature. Is it therefore correct to say that an isothermal process is the same as an adiabatic process for an ideal gas? Explain your answer.
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An ideal monatomic gas expands slowly to twice its volume
(1) isothermally; (2) adiabatically; (3) isobarically. Plot
each on a PV diagram. In which process is AU the greatest,
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and the least? In which is Q the greatest and the least?
Consider the following idealized heat engine:|
Th
Qn Wout
Q. ]
T.
Here, the box labeled Tħ corresponds to a thermal reservoir at temperature Th, the box
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positive amount of work Wout and an amount of heat Qc flows into the cold thermal
reservoir. (With this convention, Qh, Qc, and Wout are all positive quantities.)
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Give your answers in terms of Qh, Th, and Tc. (Advice: be careful of your signs.)
1. Qc+ Wout
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In a cylinder, 1.20mol of an ideal monatomic gas, initially at 3.60×105Pa and 300K, expands until its volume triples.
Compute the work done by the gas if the expansion is adiabatic.
I need a thorough explanation as to HOW to do it. I know that:
W = -nCv(Delta T)
In another solution, someone said W = -nCvT1(1-(1/3)^2/3).......why??? I need to understand it.
Chapter 3 Solutions
University Physics Volume 2
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