Genetic Analysis: An Integrated Approach (2nd Edition)
Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 3, Problem 10P
Summary Introduction

To analyze:

The number of Barr bodies in female and male nucleus.

Introduction:

The first visualization of Barr body was by Murray Barr-1949. Barr body is a dense structure of chromatin, forms in the nuclei of female somatic cells. In humans, females have two X chromosomes and males have one X and one Y chromosomes. The sex cells or gamete cells are the only cells that take part in sexual reproduction while the remaining cells are called somatic cells that do not participate in the process. In females, one X chromosome is active while another X is inactivated through the process of lionization, and it becomes a Barr body. In order to have an equal amount of X chromosome expression in both males and females, X inactivation is necessary; otherwise the amount of genetic information expressed will be two fold or more. The selection of X chromosome to be inactivated is random, but once the active and inactive X chromosomes are selected, the descendent cells will have the same X chromosome active and inactive.

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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin

Chapter 3 Solutions

Genetic Analysis: An Integrated Approach (2nd Edition)

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