Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 29, Problem 8P
Alternative Splicing Possibilities Suppose exon 17 were deleted from the fast skeletal muscle troponin T gene (Figure 29.46). How many different mRNAs could now be generated by alternative splicing? Suppose that exon 7 in a wild-type troponin T gene were duplicated. How many different mRNAs might be generated from a transcript of this new gene by alternative splicing?
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Chapter 29 Solutions
Biochemistry
Ch. 29 - Prob. 1PCh. 29 - The Events in Transcription Initiation Describe...Ch. 29 - Substrate Binding by RNA Polymerase RNA polymerase...Ch. 29 - Comparison of Prokaryotic and Eukaryotic...Ch. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Alternative Splicing Possibilities Suppose exon 17...Ch. 29 - Prob. 9PCh. 29 - Prob. 10P
Ch. 29 - Post-transcriptional Modification of Eukaryotic...Ch. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - The Lariat Intermediate in RNA Splicing Draw the...Ch. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Figure 29.15 highlights in red the DNA phosphate...Ch. 29 - Chromatin decompaction is a preliminary step in...
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- Give typed full explanationarrow_forwardThe products of alternative splicing for the α-tropomyosin pre-mRNA. Let’s suppose that smooth muscle cells produce splicing factors that are not produced in other cell types. Explain where you think such splicing factors bind and how they influence the splicing of the α-tropomyosin pre-mRNA.arrow_forwardBriefly discuss (referring to the images provided) why mutant 2 fails to produce functional protein. Note that none of the mRNA transcribed from this gene is of the expected size; some of the mRNA molecules produced are 223 nucleotides shorter than expected, whilst others are 47 nucleotides longer than expected.arrow_forward
- Molecular biologyarrow_forwardAminoacyl-tRNA synthetases are the only component of gene expression that decodes the genetic code. Explain.arrow_forwardIn eukaryotes there is not a consistent relationship between the length of the coding sequence of a gene and the length of the mature mRNA it encodes, even though one nucleotide in DNA = one nucleotide in pre-mRNA or primary transcript. Explain why this is so.arrow_forward
- Recall from the central dogma that DNA codes for mRNA, which then codes for protein. Also recall that directionality matters! DNA 3' TAC - CTA -AAT - TGC - TCG-ATT 5' mRNA 5' ???- ???- ???- ???- ???- ??? 3' protein ? ? ? ? ? (A) Indicate whether the DNA sequence provided is the sense strand or the antisense strand. ? that (B) For the DNA sequence given above, write out the mRNA sequence that results. (C) Now write the amino acid sequence that results from the mRNA sequence you wrote in part (B). Use the three-letter abbreviations for the amino acids. (D) What happens if the A that is bolded and underlined in the given DNA sequence is mutated (changed) to a C? How is the protein affected? This can be answered in a few words, but be specific! (E) Now let's pretend for a moment that the protein being affected is ATP-ADP translocase. What, if anything, would happen to the citric acid cycle? This should be answered in a few words/one sentence max.arrow_forwardSuppose an mRNA transcript with the following base sequence reaches a ribosome: 5' AUGCGUUAUGGCUACUGA - 3' Give the primary structure of the protein that the ribosome will build, by writing the 3-letter codes of the amino acid residues in the usual order (N- to C-terminus). If there is more than one possible protein that will be produced, write the amino acid residue sequence for any of them. You will find some useful information about the genetic code and amino acids in the ALEKS Data resource. I Don't Know Submit O 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Acce DELL F4 F10 F11 F12 PrtScr Insert Delete PgL F1 F2 F3 F5 F6 F7 F8 F9 "R %2# $4 & Backspacearrow_forwardThe diagram below depicts an active transcription bubble after a short period of RNA synthesis during the transcription process of a prokaryotic gene. Redraw the diagram and label parts (i) to (v) on the diagram. Motivate your answers. (i) the template and the non-template strands; (ii) the orientation (direction) of both DNA strands and that of the newly synthesised RNA strand; (iii) the location of a possible promotor sequence; (iv) the location of a possible Shine-Dalgarno sequence; (v) the specific area of activity of a RNA polymerase.arrow_forward
- Give detailed Solution with explanation needed..don't give Handwritten answer..don't use Ai for answering thisarrow_forwardEditing during DNA replication is provided by DNA polymerase enzymatic activity of O 5'-> 3' polymerase 3'-> 5' polymerase O 3'-> 5' exonuclease O an extra enzyme that binds to DNA polymerase O 5'-> 3'exonucleasearrow_forwardIntrons in protein-coding genes of some eukaryotes are rarely shorter than 65 nucleotides long. What might be a rationale for this limitation?arrow_forward
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