Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Textbook Question
Chapter 29, Problem 11P
Post-transcriptional Modification of Eukaryotic mRNAs What might be the advantages of capping, methylation, and polyadenylylation of eukaryotic mRNAs?
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Introns in protein-coding genes of some eukaryotes are rarely shorter than
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In eukaryotes there is not a consistent relationship between the length of the coding sequence of a gene and the length of the mature mRNA it encodes, even though one nucleotide in DNA = one nucleotide in pre-mRNA or primary transcript. Explain why this is so.
How would a null mutation in the guanylyl transferase gene affect overall mRNA stability in eukaryotic cells?
Chapter 29 Solutions
Biochemistry
Ch. 29 - Prob. 1PCh. 29 - The Events in Transcription Initiation Describe...Ch. 29 - Substrate Binding by RNA Polymerase RNA polymerase...Ch. 29 - Comparison of Prokaryotic and Eukaryotic...Ch. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Alternative Splicing Possibilities Suppose exon 17...Ch. 29 - Prob. 9PCh. 29 - Prob. 10P
Ch. 29 - Post-transcriptional Modification of Eukaryotic...Ch. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - The Lariat Intermediate in RNA Splicing Draw the...Ch. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Figure 29.15 highlights in red the DNA phosphate...Ch. 29 - Chromatin decompaction is a preliminary step in...
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- Keeping in mind the three main processing events that occur in eukaryotes (5' capping, 3' cleavage and intron splicing) would it be reasonable to conclude that the mature RNA would contains exons, a promoter region (to the left of the transcription site) and a poly A tail?arrow_forwardWhat molecular biology strategy can best be used to determine Inhibition of the splicing of one intron from the parental RNA resulting in a longer protein product? Explain.arrow_forwardsome eukaryotic mRNAs have internal ribosome binding sites, where ribosomes can bind without first attaching to the 5′ cap. Yet all eukaryotic mRNAs are capped, and cap-dependent translation is highly efficient. What might be the advantage of having internal ribosome binding sites if the cap permits the initiation of translation and all eukaryotic mRNAs are capped?arrow_forward
- Transcription occurs at a rate of about 30 nucleotides per second. is it possible to calculate the time required to synthesize a titin mRNA from the information given here?arrow_forwardexon 1 еxon 2 exon 3 exon 4 5' 3' 13' DNA 15' TRANSCRIPTION exon 1 exon 2 exon 3 exon 4 13' pre-MRNA ALTERNATIVE SPLICING 1 2 3 4 1 4 A В two alternative MRNAS Without knowing the DNA (or RNA) sequence, describe an experiment that would show you the difference between the two alternative MRNAS (labeled A and B) shown for this hypothetical gene. Specifically, how would you know A) How many exons each alternative mRNA contains? You can just describe the result B) Which exons they were? You can just describe the result. min inarrow_forwardhelparrow_forward
- "Upstream" "Downstream" Exons Start of transcription Termination codon 5 3' Promoter initiator codon Introns Polyadenylation signal (intervening sequences) 5' untranslated region 3' untranslated region Direction of transcription Please study the diagram above on eukaryotic gene expression. In order to provide instructions for gene expression, a eukaryotic gene should have the following sequences except for O A. Promoter B. Start codon also known as initiator codon C. Splicing signals (dinucleotide sequence in the intron) O D. 5' CAP sequencearrow_forwardmRNA stability is a key regulator of protein levels in a cell. Briefly describe the three mRNA degradation pathways. Suppose that a yeast cell has a mutation in the DCP1 gene, resulting in decreased uncapping activity. Would you expect to see a change in the P bodies found in this mutant cell?arrow_forwardIntrons in eukaryotic protein-coding genes are rarely shorter than 65 nucleotides in length. What might be a rationale for this limita- tion?arrow_forward
- Di- and trinucleotides are occasionally released from RNA polymerase at the very start of transcription, a process called abortive cycling. This process requires the restart of transcription. Suggest a plausible explanation for abortive cycling.arrow_forwardWhat is the total size of the mature i.e. fully processed mRNA in nucleotides? How many amino acids would the encoded protein be? Assume that the N- terminal Met encoded by the AUG start codon, is NOT cleaved from the protein?arrow_forwardAll eukaryotes possess a surveillance pathway referred to asnon-sense-mediated mRNA decay (NMD). Its principalfunction is to eliminate mRNA transcripts with prematurestop codons. Such faulty transcripts are detected duringtranslation and subsequently destroyed by removal of the 5′cap followed by degradation by a nuclease. Describe howpremature stop codons are detected and what type of errorcauses them.arrow_forward
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