Biochemistry
Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 29, Problem 19P

Figure 29.15 highlights in red the DNA phosphate oxygen atoms. Some of them interact with catabolite activator protein (CAP). What kind of interactions do you suppose predominate, and what kinds of CAP amino acid side chains might be involved in these interactions?

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Within a protein, certain amino acids are positively charged (e.g.,lysine and arginine), some are negatively charged (e.g., glutamateand aspartate), some are polar but uncharged, and some are nonpolar.If you knew that a DNA-binding protein was recognizingthe DNA backbone rather than a base sequence, which aminoacids in the protein would be good candidates for interacting withthe DNA?
The genetic information contained in DNA consists of a linear sequence of coding units known as codons. Each codon consists of three adjacent DNA nucleotides that corresponto a single amino acid in a protien.  The E.coli DNA molecule contains 4.70 x 10^6 base pairs. Determine the number of codons that can be present.  Assuming that the average protein in E.coli consists of a chain of 400 amino acids, calculate the maximum number of protiens that can be coded by an E.coli DNA molecule.
Figure 3 represents one process that occurs during protein synthesis. amino acid molecule Q A UGC C GỤ AC C GAC Ų (a) Name the process shown. (b) Identify the molecule labelled Q. (c) In Figure 3, the first codon is AUG. Give the base sequence of the complementary DNA base sequence and the missing anticodon. Table 1 shows the base triplets that code for two amino acids. Table 1 Amino acid Encoding base triplet Aspartic acid GAC, GAU Proline CCA, CCG, CCC, CCU Aspartic acid and proline are both amino acids. (d) Describe how two amino acids differ from one another. You may use a diagram to help your description. (e) Deletion of the sixth base (G) in the sequence shown in Figure 3 would change the nature of the protein produced but substitution of the same base would not. Use the information in Table 1 and your own knowledge to explain why.
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