Chapter 28, Problem 60A

To determine

To calculate: Electric field strength.

Answer to Problem 60A

Electric field strength = $\underset{\_}{9\times {10}^4\text{ N/C}}$

Explanation of Solution

Given:

Test charge = $+3.00\times {10}^{-7}\text{ C}$

Force = $\text{0}\text{.027 N}$

Formula used:

Electric field strength is given by,

  $E=\frac{F}{q}$

Where $F$ is the force and $q$ is the test charge.

Calculation:

Electric field strength is calculated as:

  $\begin{array}{l}E=\frac{F}{q}\\ \text{ =}\frac{0.027\text{ N}}{3.00\times {10}^{-7}\text{ C}}\\ \text{ =9}\times {\text{10}}^4\text{ N/C}\end{array}$

Conclusion:

Electric field strength = $\underset{\_}{9\times {10}^4\text{ N/C}}$