Chapter 28, Problem 29A

To determine

To Calculate: The energy level to which calcium atom is raised.

Answer to Problem 29A

  $E_6=3.91\text{eV}$

Explanation of Solution

Given:

Energy of the photon, $\Delta E=2.03\text{eV}$

Energy of lower level, $E_2=1.88\text{eV}$

Formula Used:

Transition energy, $\Delta E=E_x-E_2$

Calculations:

Substitute the values and solve.

  $\begin{array}{l}\Delta E=E_x-E_2\\ 2.03\text{eV }=E_x-1.88\text{eV}\\ E_6=3.91\text{eV}\end{array}$

Conclusion:

Thus, the energy level to which calcium atom is raised is $E_6=3.91\text{eV}$ .