Chapter 28, Problem 59A

To determine

To calculate: The EMF induced in the wire.

Answer to Problem 59A

EMF induced in the wire = $\underset{\_}{\text{2}\times {10}^{-4}\text{ V}}$

Explanation of Solution

Given:

The following diagram:

  

Length of wire = $\text{1 m}$

Velocity = $\text{4 m/s}$

Strength of magnetic field = $\text{5}\text{.0}\times {\text{10}}^{-5}\text{ T}$

Formula used:

  $EMF$ induced is given by the formula:

  $EMF\text{=}Blv$

Where $B$ is the strength of the magnetic field, $l$ is length of the wire and $v$ is the velocity.

Calculation:

  $EMF$ induced is calculated as:

  $\begin{array}{l}EMF\text{=}Blv\\ \text{ =(5}\text{.0}\times {\text{10}}^{-5}\text{ T})(1.0\text{ m)(4 m/s})\\ \text{ =2}\times {10}^{-4}\text{ V}\end{array}$

Conclusion:

EMF induced in the wire = $\underset{\_}{\text{2}\times {10}^{-4}\text{ V}}$