Concept explainers
(a)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and
Answer to Problem 28.50P
The product formed by the treatment of
Explanation of Solution
The conversion of hydroxyl groups of
Figure 1
The product formed by the treatment of
(b)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and alkyl halide.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The two anomers are formed by the treatment of monosaccharides with methanol in the presence of hydrochloric acid. One product with methoxy group on the equatorial position and other product with methoxy group on the axial position. The corresponding chemical reaction is shown below.
Figure 2
The products formed by the treatment of
(c)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and alkyl halide.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The conversion of hydroxyl groups of product
Figure 3
The product formed by the treatment of
(d)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and alkyl halide.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The first step is the conversion of hydroxyl groups of gulose into the ether groups in the presence of
Figure 4
The products formed by the treatment of
(e)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and alkyl halide.
Answer to Problem 28.50P
The product formed by the treatment of
Explanation of Solution
In the presence of acetic anhydride and pyridine, the conversion of alcoholic groups in
Figure 5
The products formed by the treatment of
(f)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and alkyl halide.
Answer to Problem 28.50P
The product formed by the treatment of
Explanation of Solution
In the presence of
Figure 7
The products formed by the treatment of
(g)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars. The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and alkyl halide.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The first step is the conversion of hydroxyl groups of gulose into the ether groups in presence of base and methyl iodide as shown in Figure 2.
The product
Figure 8
The products formed by the treatment of
(h)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars The hydroxyl groups of monosaccharides are converted into the ester groups in presence of base and acetic anhydride or acetyl chloride.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The conversion of alcoholic groups of product
Figure 9
The products formed by the treatment of
(i)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars The hydroxyl groups of monosaccharides are converted into the ester groups in presence of base and acetic anhydride or acetyl chloride.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The conversion of the product
Figure 10
The products formed by the treatment of
(j)
Interpretation: The product formed by the treatment of
Concept introduction: Monosaccharides are the small units of simple sugars The hydroxyl groups of monosaccharides are converted into the ester groups in presence of base and acetic anhydride or acetyl chloride.
Answer to Problem 28.50P
The products formed by the treatment of
Explanation of Solution
The conversion of the product
Figure 11
The products formed by the treatment of
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Chapter 28 Solutions
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- 2. Identify the type of glycosidic bond that links the monosaccharides and the structure of the disaccharide as a- or 8-isomer. CH,OH H. H OH H CH: H но OH H OH H H. OH H. OHarrow_forwarda. In an aqueous solution, d-glucose exists in equilibrium with two six-membered ring compounds. Draw the structures of these compounds.b. Which of the six-membered ring compounds will be the major product?arrow_forwardConsider the structure of carbohydrate, MANNY,arrow_forward
- Classify each monosaccharide by the type of carbonyl group and the number of carbons in the chain.arrow_forwardWhich statement(s) is(are) correct regarding the formation of maltose? A. Hydrolysis reaction between alpha-D-glucose and beta-D-glucose B. Condensation reaction between alpha-D- glucose and beta-D-glucose C. Condensation reaction between beta- galactose and beta-glucose D. Hydrolysis of starch into a di-saccharide product B & C A & B B & D C & D B, C & Darrow_forwardClassify the following disaccharide. a. beta 1-2 disaccharide b. alpha 1-4 disaccharide c. alpha 1-6 disaccharide d. alpha 1-2 disaccharide e. beta 1-4 disaccharide f. beta 1-6 disaccharidearrow_forward
- What type of glycosidic bond is shown here? CH2OH H. H. H. OH H. OH CH2 H. HO H. H. HO H. HO. OH H. HO. a(1→6) 工 エarrow_forwardIdentify the glycosidic bond indicated in the following structure. CH2OH H H. OH H O. но H. OH CH2 H. H H. QH H OH H. O B-1,4-glycosidic bond O a-1,6-glycosidic bond O a-1,4-glycosidic bond O B-1,6-glycosidic bondarrow_forwardDraw the left and right saccharide formed when the disaccharide is hydrolyzed?arrow_forward
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