The structure for the given compound should be drawn. Concept Introduction: Glycerol: The catabolism of fat which actually contain 3 R − C O O R groups is hydrolyzed and forms glycerol and long chain unbranched carboxylic acid with even number of carbons. Glycerol is polyol compound and its structure is as follows, which is actually the base of all lipids. Adenosine triphosphate ATP: The main job of ATP is to store energy and release it when cell is in need of energy. Kinase: It is enzyme which serves as a catalyst in reaction of transferring phosphoryl group into the substrate. Substrate: The molecule where the reaction takes place with help of enzymes. R and S nomenclature: it is used to assign the molecule using CIP rules. The CIP rules are as follows: Select the chiral carbon and assign the numbers according to the decreasing atomic mass of atoms attached to it. If the numbering follows clockwise direction then the molecule is termed as R and if it follows anti-clockwise direction then molecule is termed as S.

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Chapter 25.6, Problem 3P

Interpretation Introduction

Interpretation:

The structure for the given compound should be drawn.

Concept Introduction:

Glycerol:

The catabolism of fat which actually contain 3 R−COOR groups is hydrolyzed and forms glycerol and long chain unbranched carboxylic acid with even number of carbons.

Glycerol is polyol compound and its structure is as follows, which is actually the base of all lipids.

Adenosine triphosphate ATP: The main job of ATP is to store energy and release it when cell is in need of energy.

Kinase: It is enzyme which serves as a catalyst in reaction of transferring phosphoryl group into the substrate.

Substrate: The molecule where the reaction takes place with help of enzymes.

R and S nomenclature: it is used to assign the molecule using CIP rules.

The CIP rules are as follows:

Select the chiral carbon and assign the numbers according to the decreasing atomic mass of atoms attached to it.

If the numbering follows clockwise direction then the molecule is termed as R and if it follows anti-clockwise direction then molecule is termed as S.

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Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br‍(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.