The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose, are to be classified. Concept introduction: Monosaccharides are classified in to aldoses and ketoses. The ending –ose indicate a carbohydrate and the prefixes aldo- and keto- indicate whether an aldehyde or keto group is present in the molecule. The number of carbons in the monosaccharide is indicated by the appropriate prefixes tri-, tetra-, penta-, hexa- and so forth. To classify: The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose.

Question

13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)! Google

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25.1, Problem 1P

Interpretation Introduction

Interpretation:

The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose, are to be classified.

Concept introduction:

Monosaccharides are classified in to aldoses and ketoses. The ending –ose indicate a carbohydrate and the prefixes aldo- and keto- indicate whether an aldehyde or keto group is present in the molecule. The number of carbons in the monosaccharide is indicated by the appropriate prefixes tri-, tetra-, penta-, hexa- and so forth.

To classify:

The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose.

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13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)! Google

Print Last Name, First Name Initial Statifically more chances to abstract one of these 6H 11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4 4th total • 6H total 래 • 4H total 21 total ZH 2H Statistical H < 3° C-H weakest - product abstraction here bund leads to thermo favored a) (6pts) How many unique mono-chlorinated products can be formed and what are the structures for the thermodynamically and statistically favored products? Product 6 Number of Unique Mono-Chlorinated Products Thermodynamically Favored Product Statistically Favored Product b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the formation of the thermodynamically favored product. Only draw the p-1 step. You do not need to include lone pairs of electrons. No enthalpy calculation necessary H H-Cl Waterfox

10. (5pts) Provide the complete arrow pushing mechanism for the chemical transformation → depicted below Use proper curved arrow notation that explicitly illustrates all bonds being broken, and all bonds formed in the transformation. Also, be sure to include all lone pairs and formal charges on all atoms involved in the flow of electrons. CH3O II HA H CH3O-H H ①

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25.1, Problem 1P

Interpretation Introduction

Interpretation:

The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose, are to be classified.

Concept introduction:

Monosaccharides are classified in to aldoses and ketoses. The ending –ose indicate a carbohydrate and the prefixes aldo- and keto- indicate whether an aldehyde or keto group is present in the molecule. The number of carbons in the monosaccharide is indicated by the appropriate prefixes tri-, tetra-, penta-, hexa- and so forth.

To classify:

The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose.

Expert Solution & Answer

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See solution

Check out sample textbook solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25.1, Problem 1P

Interpretation Introduction

Interpretation:

The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose, are to be classified.

Concept introduction:

Monosaccharides are classified in to aldoses and ketoses. The ending –ose indicate a carbohydrate and the prefixes aldo- and keto- indicate whether an aldehyde or keto group is present in the molecule. The number of carbons in the monosaccharide is indicated by the appropriate prefixes tri-, tetra-, penta-, hexa- and so forth.

To classify:

The monosaccharides, threose, ribulose, tagatose and 2-deoxyribose.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25.1, Problem 1P

Interpretation Introduction