Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 25.SE, Problem 46AP
Interpretation Introduction

a)

Organic Chemistry, Chapter 25.SE, Problem 46AP , additional homework tip  1

Interpretation:

The open-chain form of the sugar given is to be drawn.

Concept introduction:

The pyranose form is a cyclic hemiacetal form with a six membered ring formed by the nucleophilic addition of the –OH group on C5 to the C1 carbonyl group. The furanose form is a cyclic hemiacetal form with a five membered ring formed by the nucleophilic addition of the –OH group on C5 to the C2 carbonyl group.

The orientation of –OH group differs in α- and β- anomers. In α- anomer the OH on C1 is cis to the –OH at the lowest chirality center in Fischer projection while in β- anomer the –OH on C1 is trans to the –OH at the lowest chirality center in Fischer projection.

D sugars have the –O- at C5 on the right in the uncoiled form while L sugars have -O- at C5 on the left.

To draw:

The open-chain form of the sugar given.

Interpretation Introduction

b)

Organic Chemistry, Chapter 25.SE, Problem 46AP , additional homework tip  2

Interpretation:

The open-chain form of the sugar given is to be drawn.

Concept introduction:

The pyranose form is a cyclic hemiacetal form with a six membered ring formed by the nucleophilic addition of the –OH group on C5 to the C1 carbonyl group. The furanose form is a cyclic hemiacetal form with a five membered ring formed by the nucleophilic addition of the –OH group on C5 to the C2 carbonyl group.

The orientation of –OH group differs in α- and β- anomers. In the α- anomer the OH on C1 is cis to the –OH at the lowest chirality center in Fischer projection, while in β- anomer the –OH on C1 is trans to the –OH at the lowest chirality center in Fischer projection.

D sugars have the –O- at C5 on the right in the uncoiled form while L sugars have -O- at C5 on the left.

To draw:

The open-chain form of the sugar given.

Interpretation Introduction

c)

Organic Chemistry, Chapter 25.SE, Problem 46AP , additional homework tip  3

Interpretation:

The open-chain form of the sugar given is to be drawn.

Concept introduction:

The pyranose form is a cyclic hemiacetal form with a six membered ring formed by the nucleophilic addition of the –OH group on C5 to the C1 carbonyl group. The furanose form is a cyclic hemiacetal form with a five membered ring formed by the nucleophilic addition of the –OH group on C5 to the C2 carbonyl group.

The orientation of –OH group differs in α- and β- anomers. In the α- anomer the OH on C1 is cis to the –OH at the lowest chirality center in Fischer projection, while in β- anomer the –OH on C1 is trans to the –OH at the lowest chirality center in Fischer projection.

D sugars have the –O- at C5 on the right in the uncoiled form while L sugars have -O- at C5 on the left.

To draw:

The open-chain form of the sugar given.

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The structural formula for the open-chain form of D-mannose is CH НО—С—Н Но-с—н Н—С—ОН Н—ҫ—ОН CH-OН (a) Is this molecule a sugar? (b) How many chiral carbons are present in the molecule? (c) Draw the structure of the six-member-ring form of this molecule.
Xylulose has the following structural formula. To what carbohydrate class does xylulose belong based on the number of carbons and carbonyl functionality?   A) aldotetrose B) aldopentose C) ketotetrose D) ketopentose E) ketohexose
In an aqueous solution, d-glucose exists in equilibrium with two six-membered ring compounds. Draw the structures of these compounds.

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