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Chapter 24, Problem 24.54EP
Interpretation Introduction

Interpretation: To contrast, the oxidation of glucose to CO2 and H2O with the oxidation of glucose to ethanol in terms of production of ATP.

Concept introduction: Adenosine triphosphate (ATP) is a molecule that is defined as the energy currency of life and provides energy to carry out the metabolic processes in the living cells. It is converted either to adenosine monophosphate (AMP) or to adenosine diphosphate (ADP) after the consumption in the metabolic processes.

The net yield of ATP for the complete oxidation of one molecule of glucose is obtained from the assembled ATP production from the glycolysis process, aerobic oxidation of pyruvate to acetyl CoA, the citric acid cycle, and the electron transport chain.

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Answer to Problem 24.54EP

When a glucose molecule is converted into ethanol, two ATP molecules are generated. The complete oxidation of glucose molecule produces CO2 and H2O. In this oxidation reaction, 30 ATP molecules are generated.

Explanation of Solution

In the glycolysis metabolic pathway, a glucose molecule breaks down and is converted into two pyruvate molecules. In this reaction, two ATP molecules are generated. The net overall equation for the glycolysis process is as follows:

Glucose+2ADP+2Pi+2NAD+2pyruvate+2NADH+2ATP+2H++2H2O

The end product in the glycolysis is pyruvate. The process of ethanol fermentation takes place in two steps. In step 1, the pyruvate molecule is converted to acetaldehyde by pyruvate decarboxylase enzymes. In step 2, acetaldehyde is reduced to ethanol by alcohol dehydrogenase enzymes. The ethanol fermentation equation is as follows:

Pyruvate+NADH+2H+Two stepsEthanol+CO2+NAD+

Combine the reaction for the conversion of pyruvate to ethanol with the net overall reaction for glycolysis to obtain an overall reaction for the ethanol production as follows:

Glucose+2ADP+2Pi2Ethanol+2CO2+2ATP+2H2O

The table for the production of ATP in the glycolysis process is as follows:

ReactionCommentsYield of ATPGlucoseGlucose 6phosphateconsumption of 1ATP1fructose 6phosphatefructose 1,6biphosphateconsumption of1ATP12(glyceraldehyde 3phosphate1,3biphosphoglycerate)eachproduces 1 cytosolic NADH _2(1,3-biphosphoglycerate3phosphoglycerate)productionof 1ATP by each reaction+22(phosphoenolpyruvate2pyruvate)productionof 1ATP by each reaction+2

The table for the production of ATP in the aerobic oxidation of pyruvate to acetyl CoA is as follows:

ReactionCommentsYield of ATP2(pyruvateacetyl CoA+CO2)production of 1NADH byeach reaction_

The overall reaction equation for the conversion of pyruvate to acetyl CoA is as follows:

Pyruvate+NAD++CoASHAcetylCoA+NADH+CO2

The table for the production of ATP in the citric acid cycle is as follows:

ReactionCommentsYield of ATP2(Isocitrateαketoglutarate+CO2)productionof 1NADH by each reaction_2(αketoglutaratesuccinyl CoA+CO2)productionof 1NADH by each reaction_2(succinyl CoAsuccinate)productionof 1GTP by each reaction+22(succinatefumarate)productionof 1FADH2 by each reaction_2(malateoxaloacetate)productionof 1NADH by each reaction_

The net overall equation for the Citric acid cycle is as follows:

Acetyl CoA+3NAD++FAD+GDP+HPO42(Pi)+2H2O2CO2+CoASH+3NADH+GTP+3H++FADH2

The table for the production of ATP in the electron transport chain and oxidative phosphorylation is as follows:

ReactionCommentsYield of ATPFormation of 2cytosolic NADH in the glycolysiseach produces 1.5 ATP+3Formation of 2 NADH in the oxidation of pyruvateeach produces 2.5 ATP+5Formation of 2 FADH2 in the citric acid cycleeach produces 1.5 ATP+3Formation of 6 NADH in the citric acid cycleeach produces 2.5 ATP+15

NADH, NAD+ and FADH2 canceled out, thus, the net overall equation for the complete oxidation of glucose is as follows:

Glucose+6O2+30ADP+30Pi6CO2+30ATP+6H2O

The net yield of ATP is 30. 30 molecules of ATP are produced by the complete oxidation of one molecule of glucose.

Conclusion

An overall reaction for the production of ethanol is obtained by the combination of the conversion reaction of pyruvate to ethanol with the net overall reaction for glycolysis. Therefore, a net gain of two ATP molecules occurs when one glucose molecule is converted to ethanol.

A net gain of two ATP molecules occurs when one glucose molecule is converted to two pyruvate molecules through the glycolysis pathway. In the citric acid cycle, a net gain of two ATP molecules occurs when two succinyl CoA molecules are converted to two succinate molecules. A net gain of 26 ATP molecules occurs in the electron transport chain and oxidative phosphorylation process. Complete oxidation of glucose molecule produces CO2 and H2O along with 30 ATP molecules.

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Chapter 24 Solutions

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card

Ch. 24.2 - Prob. 6QQCh. 24.2 - Prob. 7QQCh. 24.3 - Prob. 1QQCh. 24.3 - Prob. 2QQCh. 24.3 - Prob. 3QQCh. 24.3 - Prob. 4QQCh. 24.3 - Accumulation of which of the following substances...Ch. 24.4 - Prob. 1QQCh. 24.4 - The net yield of ATP for the complete oxidation of...Ch. 24.4 - Prob. 3QQCh. 24.5 - Prob. 1QQCh. 24.5 - Prob. 2QQCh. 24.5 - Prob. 3QQCh. 24.6 - Prob. 1QQCh. 24.6 - Prob. 2QQCh. 24.6 - Prob. 3QQCh. 24.6 - Which of the following statements about ATP...Ch. 24.6 - Prob. 5QQCh. 24.7 - Prob. 1QQCh. 24.7 - Prob. 2QQCh. 24.8 - Prob. 1QQCh. 24.8 - Prob. 2QQCh. 24.8 - Prob. 3QQCh. 24.9 - Which of the following hormones promotes the...Ch. 24.9 - Which of the following pairs of hormones increases...Ch. 24.10 - Prob. 1QQCh. 24.10 - Prob. 2QQCh. 24.10 - Prob. 3QQCh. 24 - Where does carbohydrate digestion begin in the...Ch. 24 - Very little digestion of carbohydrates occurs in...Ch. 24 - Prob. 24.3EPCh. 24 - Prob. 24.4EPCh. 24 - Prob. 24.5EPCh. 24 - Prob. 24.6EPCh. 24 - Prob. 24.7EPCh. 24 - Prob. 24.8EPCh. 24 - Prob. 24.9EPCh. 24 - Prob. 24.10EPCh. 24 - Prob. 24.11EPCh. 24 - Prob. 24.12EPCh. 24 - Prob. 24.13EPCh. 24 - Prob. 24.14EPCh. 24 - Prob. 24.15EPCh. 24 - Prob. 24.16EPCh. 24 - Prob. 24.17EPCh. 24 - Prob. 24.18EPCh. 24 - Prob. 24.19EPCh. 24 - Prob. 24.20EPCh. 24 - Prob. 24.21EPCh. 24 - Prob. 24.22EPCh. 24 - Prob. 24.23EPCh. 24 - Prob. 24.24EPCh. 24 - Prob. 24.25EPCh. 24 - Prob. 24.26EPCh. 24 - Prob. 24.27EPCh. 24 - Prob. 24.28EPCh. 24 - Prob. 24.29EPCh. 24 - Prob. 24.30EPCh. 24 - Prob. 24.31EPCh. 24 - Prob. 24.32EPCh. 24 - Prob. 24.33EPCh. 24 - Prob. 24.34EPCh. 24 - Prob. 24.35EPCh. 24 - Prob. 24.36EPCh. 24 - Prob. 24.37EPCh. 24 - Prob. 24.38EPCh. 24 - Prob. 24.39EPCh. 24 - Prob. 24.40EPCh. 24 - Prob. 24.41EPCh. 24 - Prob. 24.42EPCh. 24 - Prob. 24.43EPCh. 24 - Prob. 24.44EPCh. 24 - Prob. 24.45EPCh. 24 - Prob. 24.46EPCh. 24 - Prob. 24.47EPCh. 24 - Prob. 24.48EPCh. 24 - Prob. 24.49EPCh. 24 - Prob. 24.50EPCh. 24 - Prob. 24.51EPCh. 24 - Prob. 24.52EPCh. 24 - Prob. 24.53EPCh. 24 - Prob. 24.54EPCh. 24 - Prob. 24.55EPCh. 24 - Prob. 24.56EPCh. 24 - Prob. 24.57EPCh. 24 - Prob. 24.58EPCh. 24 - Prob. 24.59EPCh. 24 - Prob. 24.60EPCh. 24 - Prob. 24.61EPCh. 24 - Prob. 24.62EPCh. 24 - Prob. 24.63EPCh. 24 - Prob. 24.64EPCh. 24 - Prob. 24.65EPCh. 24 - The liver, but not the brain or muscle cells, has...Ch. 24 - Prob. 24.67EPCh. 24 - Prob. 24.68EPCh. 24 - Prob. 24.69EPCh. 24 - Prob. 24.70EPCh. 24 - Prob. 24.71EPCh. 24 - Prob. 24.72EPCh. 24 - Prob. 24.73EPCh. 24 - Prob. 24.74EPCh. 24 - Prob. 24.75EPCh. 24 - Prob. 24.76EPCh. 24 - Prob. 24.77EPCh. 24 - Prob. 24.78EPCh. 24 - Prob. 24.79EPCh. 24 - Prob. 24.80EPCh. 24 - Prob. 24.81EPCh. 24 - Prob. 24.82EPCh. 24 - Prob. 24.83EPCh. 24 - Prob. 24.84EPCh. 24 - Prob. 24.85EPCh. 24 - Prob. 24.86EPCh. 24 - Prob. 24.87EPCh. 24 - Prob. 24.88EPCh. 24 - Prob. 24.89EPCh. 24 - Prob. 24.90EPCh. 24 - Prob. 24.91EPCh. 24 - Prob. 24.92EPCh. 24 - Prob. 24.93EPCh. 24 - Prob. 24.94EPCh. 24 - Prob. 24.95EPCh. 24 - Prob. 24.96EPCh. 24 - Prob. 24.97EPCh. 24 - Prob. 24.98EPCh. 24 - Prob. 24.99EPCh. 24 - Prob. 24.100EPCh. 24 - Prob. 24.101EPCh. 24 - Prob. 24.102EPCh. 24 - Prob. 24.103EPCh. 24 - Prob. 24.104EPCh. 24 - Prob. 24.105EPCh. 24 - Prob. 24.106EPCh. 24 - Prob. 24.107EPCh. 24 - Prob. 24.108EPCh. 24 - Prob. 24.109EPCh. 24 - Prob. 24.110EPCh. 24 - Prob. 24.111EPCh. 24 - Prob. 24.112EPCh. 24 - Prob. 24.113EPCh. 24 - Prob. 24.114EPCh. 24 - Prob. 24.115EPCh. 24 - Compare the biological functions of glucagon and...Ch. 24 - Prob. 24.117EPCh. 24 - Prob. 24.118EP
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