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Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 23, Problem 44QTP
A 0.30-in.-diameter drill is used on a drill press operating at 300 rpm. If the feed is 0.005 in./rev, what is the MRR? What is the MRR if the drill diameter is doubled?
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Students have asked these similar questions
Handwritten solution recommended.
(1) A twist drill bit is used to drill a hole of diameter 2.0 at 4578.1 rpm at a feed rate of 2.5 in/min. Calculate the MRR in in^3/min. Take "pi" = 3.14. Round your answer to the nearest tenth.
The outline of the part in the Figure below is to be profile milled using a 20-
mm diameter end mill with two teeth. The part is 10 mm thick. The cutting
speed = 125 m/min and feed = 0.10 mm/tooth. The part is also to be drilled with a
drill size of 10 mm corresponds to
T01 with a cutting speed =75
mm/min and feed = 0.08 mm/rev.
The two holes pass completely
through the part.
30 rad.
125.75
10 dia., 2 holes
Write the part program (G & M code
program) for the required machining
processes. Use absolute
programming with the lower left
25
corner of the part as the origin in
the x-y axis system.
150
(All dimensions are in mm.)
25
50
75
35 deg.
A mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine.
Using the given data find the following.
(i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm
(ii) During machining the tool's approach length is 5 mm, over run length is 2mm
(iii) Total time required to complete the turning operation is 59.6 minutes
Chapter 23 Solutions
Manufacturing Engineering & Technology
Ch. 23 - Describe the types of machining operations that...Ch. 23 - What is turning? What kind of chips are produced...Ch. 23 - What is the thrust force in turning? What is the...Ch. 23 - What are the components of a lathe?Ch. 23 - (a) What is a tracer lathe? (b) What is an...Ch. 23 - Describe the operations that can be performed on a...Ch. 23 - Why were power chucks developed?Ch. 23 - Explain why operations such as boring on a lathe...Ch. 23 - Why are turret lathes typically equipped with more...Ch. 23 - Describe the differences between boring a...
Ch. 23 - How is drill life determined?Ch. 23 - What is the difference between a conventional...Ch. 23 - Why are reaming operations performed?Ch. 23 - Explain the functions of the saddle on a lathe.Ch. 23 - Describe the relative advantages of (a)...Ch. 23 - Explain how external threads are cut on a lathe.Ch. 23 - Prob. 17RQCh. 23 - Explain the reasoning behind the various design...Ch. 23 - Note that both the terms tool strength and...Ch. 23 - (a) List and explain the factors that contribute...Ch. 23 - Explain why the sequence of drilling, boring, and...Ch. 23 - Why would machining operations be necessary even...Ch. 23 - A highly oxidized and uneven round bar is being...Ch. 23 - Describe the difficulties that may be encountered...Ch. 23 - (a) Does the force or torque in drilling change as...Ch. 23 - Explain the similarities and differences in the...Ch. 23 - Describe the advantages and applications of having...Ch. 23 - Assume that you are asked to perform a boring...Ch. 23 - Explain the reasons for the major trend that has...Ch. 23 - Describe your observations concerning the contents...Ch. 23 - The footnote to Table 23.12 states that as the...Ch. 23 - In modern manufacturing, which types of metal...Ch. 23 - Sketch the tooling marks you would expect if a...Ch. 23 - What concerns would you have in turning a powder...Ch. 23 - The operational severity for reaming is much lower...Ch. 23 - Review Fig. 23.6, and comment on the factors...Ch. 23 - Explain how gun drills remain centered during...Ch. 23 - Comment on the magnitude of the wedge angle on the...Ch. 23 - If inserts are used in a drill bit (see Fig....Ch. 23 - Refer to Fig. 23.11b, and in addition to the tools...Ch. 23 - Calculate the same quantities as in Example 23.1...Ch. 23 - Estimate the machining time required to rough turn...Ch. 23 - A high-strength cast-iron bar 8 in. in diameter is...Ch. 23 - A 0.30-in.-diameter drill is used on a drill press...Ch. 23 - In Example 23.4, assume that the workpiece...Ch. 23 - For the data in Problem 23.45, calculate the power...Ch. 23 - A 6-in.-diameter aluminum cylinder 10 in. in...Ch. 23 - A lathe is set up to machine a taper on a bar...Ch. 23 - Assuming that the coefficient of friction is 0.25,...Ch. 23 - A 3-in.-diameter, gray cast iron cylindrical part...Ch. 23 - Would you consider the machining processes...Ch. 23 - Would it be difficult to use the machining...Ch. 23 - If a bolt breaks in a hole, it typically is...Ch. 23 - An important trend in machining operations is the...Ch. 23 - Review Fig. 23.8d, and explain if it would be...Ch. 23 - Boring bars can be designed with internal damping...Ch. 23 - A large bolt is to be produced from extruded...Ch. 23 - Make a comprehensive table of the process...
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- A mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 59.6 minutes (a) Find number of passes to finish the entire turning operation ( (b) The actual length of the turning operation in mm ('arrow_forwardA twin-spindle drill simultaneously drills one ½-in hole and one ¾" through a 1" wide work piece. Both holes are twist drill with 118° point angles. cutting speed for material is 230 ft/min. The rotation speed of each spindle can be configured individually. The feed rate of both holes must be set to the same value, since both spindles go down at the same speed. The forward speed is set in such a way that the speed total metal removal does not exceed 1.50 in3 /min. Determine: a) the velocity maximum feedrate (in/min) that can be used, b) the individual feedrates (in/rev) that result in each hole and c) the time required to drill the holes.arrow_forwardA mild steel specimen of Initial diameter of 51.5 mm is turned to final diameter of 48 mm for an initial length of 151 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.1 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 7 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 48.8 minutes (a) Find number of passes to finish the entire turning operation (b) The actual length of the turning operation in mm ( (c)The time required to complete one single turning operation in minutes (d) Spindle speed in rpmarrow_forward
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