Explanation Given information: The function F ( t ) = cos ( e t 2 ) . Formula used: If a function f is continuous at a point say a then lim x → a f ( x ) is the value of the function at that point that is lim x → a f ( x ) = f ( a ) , plug the limit in the function to evaluate the value. Calculation: Consider the provided function, F ( t ) = cos ( e t 2 ) . The value of the expression lim t → 2 F ( t ) is evaluated when t is substitute as 2 in the expression F ( t ) = cos ( e t 2 ) , lim t → 2 F ( t ) = lim t → 2 cos ( e t 2 ) = cos ( e 2 2 ) = 0.58 The value of the function F ( t ) = cos ( e t 2 ) , 0.1 below the limiting argument that is t = 1.9 , F ( 1.9 ) = cos ( e ( 1.9 ) 2 ) = 0.8 The value of the function F ( t ) = cos ( e t 2 ) , 0

Modeling the Dynamics of Life: Calculus and Probability for Life Scientists

3rd Edition

ISBN: 9780840064189

Author: Frederick R. Adler

Publisher: Cengage Learning

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 2.3, Problem 18E

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To calculate: The value of the expression limt→2F(t) , where F(t)=cos(et2) . Also estimate the value of function 0.1 and 0.01 above and below the limiting argument.

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Chapter 2.3, Problem 17E

Chapter 2.3, Problem 19E

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Chapter 2 Solutions

Modeling the Dynamics of Life: Calculus and Probability for Life Scientists

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The value of the expression lim t → 2 F ( t ) , where F ( t ) = cos ( e t 2 ) . Also estimate the value of function 0.1 and 0.01 above and below the limiting argument.

Solution Summary: The author calculates the value of the expression undersett to 2mathrmlimF(t).

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To calculate: The value of the expression limt→2F(t) , where F(t)=cos(et2) . Also estimate the value of function 0.1 and 0.01 above and below the limiting argument.

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Chapter 2 Solutions