
Concept explainers
(a)
Interpretation:
For the complex
- (a) Geometry of complex ion
- (b) Color absorption in whether red or blue
- (c) Whether high spin or low spin complex
Concept Introduction:
Complex compounds are primarily formed by
Complex compounds exist in following geometries - tetrahedral, square planar, octahedral etc.
Spectrochemical series refers to the arrangement of ligands with respect to crystal field splitting they cause in the d-orbitals of a metal ion. The ligand that causes larger splitting pattern is referred to as stronger ligand.
The ligands are arranged in increasing order of crystal field splitting they produce.
The ligand that causes larger crystal field splitting is strong ligand and the ligand that causes smaller splitting is termed as weak ligand.
Depending upon magnetic property Complexes are of two types - low spin complex and high spin complex. A complex is said to be low-spin if it doesn't have unpaired electrons whereas in high spin complex there will be presence of unpaired electrons. Stronger ligands pair the electrons and produce diamagnetic, low-spin complexes. Weaker ligands are incapable of pairing the electrons and form paramagnetic, high-spin complexes.
Almost all the Co-ordination compounds are colored compounds. Presence of unpaired electrons in a complex compound makes it colored as the unpaired electrons undergo transition from lower energy level to higher energy level. The color of the complex observed is complementary to the color absorbed in the wavelength region.
(a)

Answer to Problem 22.82QP
The complex ion is octahedral in geometry.
Explanation of Solution
The complex ion
(b)
Interpretation:
For the complex
- (a) Geometry of complex ion
- (b) Color absorption in whether red or blue
- (c) Whether high spin or low spin complex
Concept Introduction:
Complex compounds are primarily formed by transition elements which are d-block elements. A co-ordination compound is known as a complex compound is made of metal atom/ion and ligand(s). Ligands are considered as Lewis bases and the central metal atom is Lewis acid. Ligands donate a pair of electron to metal ion and establishes bonding with metal ion which is known as co-ordinate bond and hence these compounds are named as co-ordination compounds. The ligands represented inside the square brackets.
Complex compounds exist in following geometries - tetrahedral, square planar, octahedral etc.
Spectrochemical series refers to the arrangement of ligands with respect to crystal field splitting they cause in the d-orbitals of a metal ion. The ligand that causes larger splitting pattern is referred to as stronger ligand.
The ligands are arranged in increasing order of crystal field splitting they produce.
The ligand that causes larger crystal field splitting is strong ligand and the ligand that causes smaller splitting is termed as weak ligand.
Depending upon magnetic property Complexes are of two types - low spin complex and high spin complex. A complex is said to be low-spin if it doesn't have unpaired electrons whereas in high spin complex there will be presence of unpaired electrons. Stronger ligands pair the electrons and produce diamagnetic, low-spin complexes. Weaker ligands are incapable of pairing the electrons and form paramagnetic, high-spin complexes.
Almost all the Co-ordination compounds are colored compounds. Presence of unpaired electrons in a complex compound makes it colored as the unpaired electrons undergo transition from lower energy level to higher energy level. The color of the complex observed is complementary to the color absorbed in the wavelength region.
(b)

Answer to Problem 22.82QP
The complex will absorb in red region.
Explanation of Solution
The complex ion
(c)
Interpretation:
For the complex
- (a) Geometry of complex ion
- (b) Color absorption in whether red or blue
- (c) Whether high spin or low spin complex
Concept Introduction:
Complex compounds are primarily formed by transition elements which are d-block elements. A co-ordination compound is known as a complex compound is made of metal atom/ion and ligand(s). Ligands are considered as Lewis bases and the central metal atom is Lewis acid. Ligands donate a pair of electron to metal ion and establishes bonding with metal ion which is known as co-ordinate bond and hence these compounds are named as co-ordination compounds. The ligands represented inside the square brackets.
Complex compounds exist in following geometries - tetrahedral, square planar, octahedral etc.
Spectrochemical series refers to the arrangement of ligands with respect to crystal field splitting they cause in the d-orbitals of a metal ion. The ligand that causes larger splitting pattern is referred to as stronger ligand.
The ligands are arranged in increasing order of crystal field splitting they produce.
The ligand that causes larger crystal field splitting is strong ligand and the ligand that causes smaller splitting is termed as weak ligand.
Depending upon magnetic property Complexes are of two types - low spin complex and high spin complex. A complex is said to be low-spin if it doesn't have unpaired electrons whereas in high spin complex there will be presence of unpaired electrons. Stronger ligands pair the electrons and produce diamagnetic, low-spin complexes. Weaker ligands are incapable of pairing the electrons and form paramagnetic, high-spin complexes.
Almost all the Co-ordination compounds are colored compounds. Presence of unpaired electrons in a complex compound makes it colored as the unpaired electrons undergo transition from lower energy level to higher energy level. The color of the complex observed is complementary to the color absorbed in the wavelength region.
(c)

Answer to Problem 22.82QP
The complex is high spin complex.
Explanation of Solution
Referring to spectrochemical series fluoro ligand is a weak ligand. Hence, it forms high spin complex. Therefore
Want to see more full solutions like this?
Chapter 22 Solutions
General Chemistry - Standalone book (MindTap Course List)
- One of the pi molecular orbitals of 1,3-butadiene (CH2=CHCH=CH2) is shown below. Please identify the number of nodal planes perpendicular to the bonding axisarrow_forwardDraw the monomers required to synthesize this condensation polymer please.arrow_forwardProvide the correct systematic name for the compound shown here. Please take into account the keyboard options belowarrow_forward
- curved arrows are used to illustrate the flow of electrons. using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s)arrow_forwardIdentify the 'cartoon' drawing of the acceptor orbital in the first mechanistic step of an electrophilic addition reaction of butadiene with HBr. Pleasearrow_forwardH- H H H H H H Identify and select all structures below that represent a constitutional isomer(s) of the compound shown above. H- H H H A. H H H H-C CI H H D. H H H H H H C C -H H C C H H H H B. H CI H H- C C H H H H E. H CI H C.arrow_forward
- Why doesn't this carry on to form a ring by deprotonating the alpha carbon and the negatively-charged carbon attacking the C=O?arrow_forward6. A solution (0.0004 M) of Fe(S2CNEt2)3 (see the structural drawing below) in chloroform has absorption bands at: 350 nm (absorbance A = 2.34); 514 nm(absorbance A = 0.0532); Calculate the molar absorptivity values for these bands. Comment on their possible nature (charge transfer transitions or d-d S N- transitions?). (4 points)arrow_forwardWhat is the mechanism for this?arrow_forward
- For questions 1-4, consider the following complexes: [Co(CN)6], [COC14]², [Cr(H2O)6]²+ 4. Room temperature (20°C) measurement of molar magnetic susceptibility (Xm) for Fe(NH4)2(SO4)2×6H2O is 1.1888 x 102 cgs (Gaussian units). Calculate effective magnetic moment and provide a number of unpaired electrons for the iron ion. Use this number to rationalize the coordination geometry around iron center. (4 points)arrow_forward7. Describe the expected 31P and 19F (where applicable) NMR spectral patterns for the following compounds (indicate number of signals and their splitting patterns). a) tetraphenyldiphosphine Ph Ph P-P Ph Ph Ph Ph ' b) tetraphenyldiphosphine monoxide P-P-Ph Ph (2 points) (2 points c) tetrafluorophosphonium hexafluorophosphate [PF4]*[PF6]¯ (4 points)arrow_forward3. For questions 1-4, consider the following complexes: [Co(CN)6]4, [COC14]², [Cr(H2O)6]²+ Which (if any) of these complexes would be expected to display Jahn-Teller distortion? (2 points)arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning





