General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN: 9781305580343
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher: Cengage Learning
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Chapter 22, Problem 22.57QP

(a)

Interpretation Introduction

Interpretation:

Using crystal field theory, the energy level diagram of d-orbitals of the complex ion [V(CN)6]3 in octahedral field has to be drawn.

Concept Introduction:

There are five d-orbitals in a metal ion. They have similar energy levels that they are degenerated. Under the influence of ligands during complex formation, the degeneracy in d-orbitals is destroyed that they are split into two sets of orbitals - one set having lower energy and the another set is higher in energy.  Crystal field splitting refers to the difference in energy levels between these two sets of d-orbitals.

When ligands approach the metal ion the degeneracy in d-orbitals of the metal ion is destroyed and they split into two different energy levels. In case of octahedral complex, the dx2y2and dz2 orbitals occupy higher energy level and the dxy,dxz,dyz orbitals occupy lower energy level.  The energy gap between these two set of orbitals is termed as crystal field splitting energy.

(a)

Expert Solution
Check Mark

Answer to Problem 22.57QP

The energy level diagram of d-orbitals of the complex ion [V(CN)6]3 is drawn as,

General Chemistry - Standalone book (MindTap Course List), Chapter 22, Problem 22.57QP , additional homework tip  1

Two unpaired electrons are present in this complex ion.

Explanation of Solution

Atomic number of Vanadium is 23 and its electronic configuration is 1s22s22p63s23p63d34s2 .  In the complex [V(CN)6]3 Vanadium is in +3 oxidation state as follows –

Oxidation state of Vanadium = charge on complex - charge of ligands = -3-[6(1)] = -3+6 = +3

The electronic configuration of V3+ is 1s22s22p63s23p63d2 . Thus there two d-electrons and they are unpaired and distributed in octahedral field as –

General Chemistry - Standalone book (MindTap Course List), Chapter 22, Problem 22.57QP , additional homework tip  2

(b)

Interpretation Introduction

Interpretation:

Using crystal field theory, the energy level diagram of d-orbitals of the high-spin complex ion [Co(C2O4)3]4 in octahedral field has to be drawn.

Concept Introduction:

There are five d-orbitals in a metal ion. They have similar energy levels that they are degenerated. Under the influence of ligands during complex formation, the degeneracy in d-orbitals is destroyed that they are split into two sets of orbitals - one set having lower energy and the another set is higher in energy.  Crystal field splitting refers to the difference in energy levels between these two sets of d-orbitals.

When ligands approach the metal ion the degeneracy in d-orbitals of the metal ion is destroyed and they split into two different energy levels. In case of octahedral complex, the dx2y2and dz2 orbitals occupy higher energy level and the dxy,dxz,dyz orbitals occupy lower energy level.  The energy gap between these two set of orbitals is termed as crystal field splitting energy.

(b)

Expert Solution
Check Mark

Answer to Problem 22.57QP

The energy level diagram of d-orbitals of the high-spin complex ion [Co(C2O4)3]4 is drawn as,

General Chemistry - Standalone book (MindTap Course List), Chapter 22, Problem 22.57QP , additional homework tip  3

There are three unpaired electrons in the complex ion [Co(C2O4)3]4 .

Explanation of Solution

Atomic number of Cobalt is 27 and its electronic configuration is 1s22s22p63s23p63d74s2 .  In the complex [Co(C2O4)3]4 Cobalt is in +2 oxidation state as follows –

Oxidation state of Cobalt = charge on complex - charge of ligands = -4-[3(2)] = -4+6 = +2

The electronic configuration of Co2+ is 1s22s22p63s23p63d7 . Given that the complex is high-spin which means it has unpaired electrons. Thus the seven d-electrons are distributed in octahedral field as –

General Chemistry - Standalone book (MindTap Course List), Chapter 22, Problem 22.57QP , additional homework tip  4

From the above arrangement we could say there are three unpaired electrons in the complex ion [Co(C2O4)3]4 .

(c)

Interpretation Introduction

Interpretation:

Using crystal field theory, the energy level diagram of d-orbitals of the low-spin complex ion [Mn(CN)6]3 in octahedral field has to be drawn.

Concept Introduction:

There are five d-orbitals in a metal ion. They have similar energy levels that they are degenerated. Under the influence of ligands during complex formation, the degeneracy in d-orbitals is destroyed that they are split into two sets of orbitals - one set having lower energy and the another set is higher in energy.  Crystal field splitting refers to the difference in energy levels between these two sets of d-orbitals.

When ligands approach the metal ion the degeneracy in d-orbitals of the metal ion is destroyed and they split into two different energy levels. In case of octahedral complex, the dx2y2and dz2 orbitals occupy higher energy level and the dxy,dxz,dyz orbitals occupy lower energy level.  The energy gap between these two set of orbitals is termed as crystal field splitting energy.

(c)

Expert Solution
Check Mark

Answer to Problem 22.57QP

The energy level diagram of d-orbitals of the low-spin complex ion [Mn(CN)6]3 is drawn as,

General Chemistry - Standalone book (MindTap Course List), Chapter 22, Problem 22.57QP , additional homework tip  5

There are two unpaired electrons in the complex ion [Mn(CN)6]3 .

Explanation of Solution

Atomic number of Manganese is 25 and its electronic configuration is 1s22s22p63s23p63d54s2 .  In the complex [Mn(CN)6]3 Manganese is in +3 oxidation state as follows –

Oxidation state of Manganese = charge on complex - charge of ligands = -3-[6(1)] = -3+6 = +3

The electronic configuration of Mn3+ is 1s22s22p63s23p63d4 . Given that the complex is low-spin which means the electrons are paired up to maximum possibility. Thus the four d-electrons are distributed in octahedral field as –

General Chemistry - Standalone book (MindTap Course List), Chapter 22, Problem 22.57QP , additional homework tip  6

From the above arrangement we could say there are two unpaired electrons in the complex ion [Mn(CN)6]3 .

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Chapter 22 Solutions

General Chemistry - Standalone book (MindTap Course List)

Ch. 22 - What characteristics of the transition elements...Ch. 22 - Prob. 22.2QPCh. 22 - Prob. 22.3QPCh. 22 - Prob. 22.4QPCh. 22 - Prob. 22.5QPCh. 22 - Prob. 22.6QPCh. 22 - Prob. 22.7QPCh. 22 - Prob. 22.8QPCh. 22 - Silver(I) ion in basic solution is reduced by...Ch. 22 - What evidence did Werner obtain to show that the...Ch. 22 - Define the terms complex ion, ligand, and...Ch. 22 - Prob. 22.12QPCh. 22 - Prob. 22.13QPCh. 22 - Prob. 22.14QPCh. 22 - Prob. 22.15QPCh. 22 - Prob. 22.16QPCh. 22 - Explain the difference in behavior of d and l...Ch. 22 - Prob. 22.18QPCh. 22 - Prob. 22.19QPCh. 22 - a Describe the steps in the formation of a...Ch. 22 - Prob. 22.21QPCh. 22 - Prob. 22.22QPCh. 22 - Prob. 22.23QPCh. 22 - Prob. 22.24QPCh. 22 - Prob. 22.25QPCh. 22 - Prob. 22.26QPCh. 22 - Prob. 22.27QPCh. 22 - Prob. 22.28QPCh. 22 - What is the correct name for the coordination...Ch. 22 - Prob. 22.30QPCh. 22 - Prob. 22.31QPCh. 22 - Prob. 22.32QPCh. 22 - Prob. 22.33QPCh. 22 - Prob. 22.34QPCh. 22 - Prob. 22.35QPCh. 22 - Prob. 22.36QPCh. 22 - Prob. 22.37QPCh. 22 - Prob. 22.38QPCh. 22 - Prob. 22.39QPCh. 22 - Prob. 22.40QPCh. 22 - Prob. 22.41QPCh. 22 - Prob. 22.42QPCh. 22 - Prob. 22.43QPCh. 22 - Prob. 22.44QPCh. 22 - Consider the complex ion [CoCl(en)2(NO2)]+. a What...Ch. 22 - Prob. 22.46QPCh. 22 - Prob. 22.47QPCh. 22 - Name the following complexes, using IUPAC rules. a...Ch. 22 - Prob. 22.49QPCh. 22 - Prob. 22.50QPCh. 22 - Prob. 22.51QPCh. 22 - Give the structural formula for each of the...Ch. 22 - Prob. 22.53QPCh. 22 - Prob. 22.54QPCh. 22 - Prob. 22.55QPCh. 22 - Prob. 22.56QPCh. 22 - Prob. 22.57QPCh. 22 - Prob. 22.58QPCh. 22 - Prob. 22.59QPCh. 22 - Prob. 22.60QPCh. 22 - Prob. 22.61QPCh. 22 - Prob. 22.62QPCh. 22 - Prob. 22.63QPCh. 22 - Prob. 22.64QPCh. 22 - Prob. 22.65QPCh. 22 - Prob. 22.66QPCh. 22 - Prob. 22.67QPCh. 22 - Prob. 22.68QPCh. 22 - There are only two geometric isomers of the...Ch. 22 - Prob. 22.70QPCh. 22 - Prob. 22.71QPCh. 22 - Prob. 22.72QPCh. 22 - Prob. 22.73QPCh. 22 - Prob. 22.74QPCh. 22 - Prob. 22.75QPCh. 22 - Prob. 22.76QPCh. 22 - Consider the complex ion [CoCO3(NH3)4], where the...Ch. 22 - Prob. 22.78QPCh. 22 - Prob. 22.79QPCh. 22 - Prob. 22.80QPCh. 22 - Prob. 22.81QPCh. 22 - Prob. 22.82QPCh. 22 - What is the name of K2[MoOCl4]?Ch. 22 - Write the formula and draw the structure of...Ch. 22 - Prob. 22.85QPCh. 22 - Prob. 22.86QPCh. 22 - Is it possible to have a paramagnetic...Ch. 22 - Prob. 22.88QPCh. 22 - Prob. 22.89QPCh. 22 - Prob. 22.90QPCh. 22 - Prob. 22.91QPCh. 22 - Prob. 22.92QP
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