Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
10th Edition
ISBN: 9781305957510
Author: ZUMDAHL, Steven S.; Zumdahl, Susan A.; DeCoste, Donald J.
Publisher: Cengage Learning
Question
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Chapter 22, Problem 168CP

(a)

Interpretation Introduction

Interpretation: The two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers are to be drawn. The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample is to be calculated and the relative numbers of monomer units in the given sample of ABS plastic is to be determined.

Concept introduction: The polymers (repeating structural units) are derived from the simple and reactive molecules, called as monomers. ABS plastic is a terpolymer of styrene, acrylonitrile and polybutadiene.

To determine: The structure of two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers.

(a)

Expert Solution
Check Mark

Answer to Problem 168CP

Answer

The two repeating units of ABS plastic are shown in Figure 1.

Explanation of Solution

Explanation

The structure of the polymer of ABS plastic is shown in figure 1.

The reaction of Abs polymer synthesis is,

Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition, Chapter 22, Problem 168CP

Figure 1

ABS plastic is a terpolymer synthesized by polymerizing styrene, acrylonitrile and polybutadiene. The chemical formula of ABS polymer is (C8H8.C4H6.C3H3N)n whose structure of two repeating units of monomers is shown in Figure 1

(b)

Interpretation Introduction

Interpretation: The two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers are to be drawn. The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample is to be calculated and the relative numbers of monomer units in the given sample of ABS plastic is to be determined.

Concept introduction: The polymers (repeating structural units) are derived from the simple and reactive molecules, called as monomers. ABS plastic is a terpolymer of styrene, acrylonitrile and polybutadiene.

To determine: The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample.

(b)

Expert Solution
Check Mark

Answer to Problem 168CP

Answer

The mass percent of acrylonitrile is 16.90%_ .

The mass percent of butadiene is 17.22%_ .

The mass percent of styrene is 33.18%_ .

Explanation of Solution

Explanation

The mass percent of the three given monomers is calculated below.

Given

The mass of bromine to react completely with ABS plastic is 0.605 g .

The mass of ABS plastic is 1.20 g .

The molar mass of bromine is 158g/mol .

The number of moles is calculated by the formula,

Numberofmoles=GivenmassMolarmass

Substitute the given value of the mass and molar mass of bromine in the above expression.

Numberofmolesofbromine=GivenmassMolarmass=0.605g158g/mol=0.003829mol

Hence, each molecule in this polymer contains 0.003829mol .

Therefore, 0.003829mol of bromine reacted with 0.003829mol of polymer.

The ABS plastic is constructed by equimolar ratio of the three molecules. Hence, each molecule is 0.003829mol .

Therefore,

The mass of acrylonitrile, styrene and butadiene is calculated as,

The molar mass of acrylonitrile is 53 g/mol .

The molar mass of butadiene is 54 g/mol .

The molar mass of styrene is 104 g/mol .

The mass of acrylonitrile, styrene and butadiene is calculated by using the formula,

Mass=Number of moles×Molar mass .

Substitute the given value of the number of moles and molar mass of in the above expression.

For acrylonitrile,

Mass of acrylonitrile=Number of moles×Molar mass=0.003829 mol×53 g/mol=0.2029 g

For butadiene,

Mass of butadiene=Number of moles×Molar mass=0.003829 mol×54 g/mol=0.2067 g

For styrene

Mass of styrene=Number of moles×Molar mass=0.003829 mol×104 g/mol=0.3982 g

Therefore,

Mass percent of acrylonitrile, styrene and butadiene is calculated as,

For acrylonitrile,

Mass percent of acrylonitrile = 0.20291.20×10016.90%_

For butadiene,

Mass percent of butadiene = 0.20671.20×10017.22%_

For styrene

Mass percent of styrene = 0.39821.20×10033.18%_

(c)

Interpretation Introduction

Interpretation: The two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers are to be drawn. The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample is to be calculated and the relative numbers of monomer units in the given sample of ABS plastic is to be determined.

Concept introduction: The polymers (repeating structural units) are derived from the simple and reactive molecules, called as monomers. ABS plastic is a terpolymer of styrene, acrylonitrile and polybutadiene.

To determine: The relative numbers of monomer units in the given sample of ABS plastic.

(c)

Expert Solution
Check Mark

Answer to Problem 168CP

Answer

The three monomer units are in 1:1:2 molar ratios respectively.

Explanation of Solution

Explanation

The relative numbers of the monomer unit in ABS sample is explained below.

On the basis of the above results it is considered that the three monomer unit’s; acrylonitrile, butadiene and styrene are present in 1:1:2 molar ratios respectively.

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Chapter 22 Solutions

Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition

Ch. 22 - Prob. 11RQCh. 22 - Describe the structural differences between DNA...Ch. 22 - Prob. 1QCh. 22 - Prob. 2QCh. 22 - Prob. 3QCh. 22 - Prob. 4QCh. 22 - Prob. 5QCh. 22 - Prob. 6QCh. 22 - Prob. 7QCh. 22 - Give an example reaction that would yield the...Ch. 22 - Prob. 9QCh. 22 - Prob. 10QCh. 22 - Prob. 11QCh. 22 - Prob. 12QCh. 22 - Is the primary, secondary, or tertiary structure...Ch. 22 - Prob. 14QCh. 22 - Prob. 15ECh. 22 - Prob. 16ECh. 22 - Draw all the structural isomers for C8H18 that...Ch. 22 - Draw all the structural isomers for C8H18 that...Ch. 22 - Prob. 19ECh. 22 - Prob. 20ECh. 22 - Draw the structural formula for each of the...Ch. 22 - Prob. 22ECh. 22 - Prob. 23ECh. 22 - Name each of the following cyclic alkanes, and...Ch. 22 - Prob. 25ECh. 22 - Draw the structures for two examples of...Ch. 22 - Name each of the following alkenes. a. CH2 = CH ...Ch. 22 - Name each of the following alkenes or alkynes. a....Ch. 22 - Prob. 29ECh. 22 - Give the structure for each of the following. a....Ch. 22 - Prob. 31ECh. 22 - Cumene is the starting material for the industrial...Ch. 22 - Name each of the following. a. b. CH3CH2CH2CCl3 c....Ch. 22 - Prob. 34ECh. 22 - There is only one compound that is named...Ch. 22 - Prob. 36ECh. 22 - Prob. 37ECh. 22 - Prob. 38ECh. 22 - Draw all the structural isomers of C5H10. 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Use bond energies (see Table 3-3) to estimate H...Ch. 22 - Prob. 143AECh. 22 - Prob. 144AECh. 22 - All amino acids have at least two functional...Ch. 22 - Prob. 146AECh. 22 - Prob. 147AECh. 22 - In glycine, the carboxylic acid group has Ka = 4.3...Ch. 22 - Name each of the following alkanes. a....Ch. 22 - Prob. 150CWPCh. 22 - Name each of the following cyclic alkanes. a. b....Ch. 22 - Name each of the following alkenes and alkynes. a....Ch. 22 - a. Name each of the following alcohols. b. Name...Ch. 22 - Prob. 154CWPCh. 22 - Prob. 155CWPCh. 22 - Prob. 156CWPCh. 22 - Prob. 157CPCh. 22 - Estimate H for the following reactions using bond...Ch. 22 - Prob. 159CPCh. 22 - Prob. 160CPCh. 22 - Prob. 161CPCh. 22 - Consider a sample of a hydrocarbon at 0.959 atm...Ch. 22 - Prob. 163CPCh. 22 - Prob. 164CPCh. 22 - Prob. 165CPCh. 22 - Prob. 166CPCh. 22 - Prob. 167CPCh. 22 - Prob. 168CPCh. 22 - Prob. 169CPCh. 22 - Alcohols are very useful starting materials for...Ch. 22 - A chemical breathalyzer test works because ethanol...Ch. 22 - Estradiol is a female hormone with the following...Ch. 22 - Prob. 173IPCh. 22 - Prob. 174IPCh. 22 - Prob. 175MPCh. 22 - Prob. 176MP
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