Chapter 21, Problem 67E

(a)

Interpretation Introduction

Interpretation: The following reaction needs to be completed.

  ${\text{CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{H+CH}}_3\text{OH}\to$

Concept Introduction : The reaction of carboxylic acid with an alcohol in presence of acid catalyst produces an ester along with water. This type of reaction is termed as Fischer esterification reaction.

Answer to Problem 67E

Complete reaction is as follows:

  $\begin{array}{l}{\text{CH}}_{\text{3}}{\text{CO}}_{\text{2}}\text{H}\text{+}{\text{CH}}_3\text{OH}\to {\text{CH}}_3{\text{COOCH}}_3+{\text{H}}_{\text{2}}\text{O}\\ \text{Ethanoic}\text{acid}\text{Methanol}\text{Methyl}\text{acetate}\text{water}\end{array}$

Explanation of Solution

Fisher esterification reaction is as follows:

  

From the above reaction, it is clear that when carboxylic acid reacts with alcohol, an ester is formed along with water.

  $\begin{array}{l}{\text{CH}}_{\text{3}}{\text{CO}}_{\text{2}}\text{H}\text{+}{\text{CH}}_3\text{OH}\to {\text{CH}}_3{\text{COOCH}}_3+{\text{H}}_{\text{2}}\text{O}\\ \text{Ethanoic}\text{acid}\text{Methanol}\text{Methyl}\text{acetate}\text{water}\end{array}$

(b)

Interpretation Introduction

Interpretation: The following reaction needs to be completed.

  ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH+HCOOH}\to$

Concept Introduction : The reaction of carboxylic acid with an alcohol in presence of acid catalyst produces an ester along with water. This type of reaction is termed as Fischer esterification reaction.

Answer to Problem 67E

Complete reaction is as follows:

  $\begin{array}{l}{\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH}\text{+}\text{HCOOH }\to {\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{COOH}\text{+}{\text{H}}_2\text{O}\\ \text{Propanol}\text{Formic acid}\text{Butanoic acid}\text{water}\end{array}$

Explanation of Solution

Fisher esterification reaction is as follows:

  

From the above reaction, it is clear that when carboxylic acid reacts with alcohol, an ester is formed along with water. In the given question carboxylic acid is formic acid. So, another carboxylic acid will form.

  $\begin{array}{l}{\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH}\text{+}\text{HCOOH }\to {\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{COOH}\text{+}{\text{H}}_2\text{O}\\ \text{Propanol}\text{Formic acid}\text{Butanoic acid}\text{water}\end{array}$