Concept explainers
A simple generator has a square armature 6.0 cm on a side. The armature has 85 turns of 0.59-mm-diameter copper wire and rotates in a 0.65-T magnetic field. The generator is used to power a lightbulb rated at 12.0V and 25.0 W. At what rate should the generator rotate to provide 12.0 V to the bulb? Consider the resistance of the wire on the armature.
The rate of the rotation of the generator to provide 12 V.
Answer to Problem 22P
Solution:
17 cycles per second.
Explanation of Solution
Given info:
Formula to be used:
The internal resistance:
The resistance of uniform metallic conductor is given by
[ =length, =area, = electrical resistivity]
Calculation:
Applying values,
[Resistivity of copper is ]
Power of the light bulb rated at 12.0 V and 25 W.
Formula used:
By using power formula,
Calculation:
Voltage drop inside the generator,
Applying values,
Therefore, the actual Emf required = +
The above value is rms value of emf
The maximum EMF (peak voltage)is given by,
For generator, by Faraday’s law,
Formula used:
Calculation:
Applying values,
Chapter 21 Solutions
Physics: Principles with Applications
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