Chapter 21, Problem 54P

To determine

To find:The frequency of a capacitor.

Answer to Problem 54P

Solution:

The frequency is 10.87 Hz.

Explanation of Solution

Given:

  $f=2.4\times {10}^{-6}\text{Hz}$

Formula: The relation between the capacitive reactance and the capacitance is given by

  $X_C=\frac{1}{2\pi fC}$

Where, f is the frequency in Hz and C is the capacitance in F.

Substituting the values of f and C in the above relation, we get

  $6100=\frac{1}{2\pi \times f\times 2.4\times {10}^{-6}}$

  $f=\frac{1}{2\pi \times 6100\times 2.4\times {10}^{-6}}=10.87\text{ Hz}$

The frequency is 10.87 Hz.

Conclusion:

Therefore, the frequency is 10.87 Hz.