Chapter 21, Problem 75GP

To determine

The number of turns a flashlight can be made that is powered by the induced current from magnet $10,000$

Answer to Problem 75GP

Solution:

Number of turns will be $10,000$

Explanation of Solution

Given info:

$\begin{array}{l}t=0.5s\\ B_0=0.05\text{T}\\ \text{A=}0.015\text{m}\end{array}$

Formula used:

$N=\frac{\xi \Delta t}{2B_{0}A}$

Where,

$\begin{array}{l}t=0.5s\\ B_0=0.05\text{T}\\ \text{A=}0.015\text{m}\end{array}$

Calculation:

$N=\frac{\xi \Delta t}{2B_{0}A}=\frac{\left(3\text{V}\right)\left(0.25\text{s}\right)}{2\left(0.05\text{T}\right)\pi {\left(0.015\text{m}\right)}^2}=10,000$