
Concept explainers
(a)
Interpretation:
The energy band for molecular orbital and electron population of a semiconductor has to be drawn. Also higher electrical conductivity of semiconductor than metallic conductor has to be explained.
Concept introduction:
Semiconductor: A material which can conduct electricity in range between a metal and an insulator is known as semiconductor. Addition of small amount of impurities increases conductivity of semiconductor and the process is known as doping. n-type and p-type are two types of doped semiconductors.
n-type: This type of doped semiconductor is the one in which many free electrons are present in conduction band.
p-type: This type of doped semiconductor is the one in which holes are present in conduction band.
Conductor: Any materials which can conducts electricity are known as conductor. There is no band gap in metallic conductor and electrons can easily travel.
(b)
Interpretation:
The energy band for molecular orbital and electron population of a metallic conductor has to be drawn.
Concept introduction:
Conductor:
Any materials which can conducts electricity are known as conductor. There is no band gap in metallic conductor and electrons can easily travel.

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Chapter 21 Solutions
General Chemistry: Atoms First
- The vapor pressure of dichloromethane at 20.0 °C is 58.0 kPa and its enthalpy of vaporization is 32.7 kJ/mol. Estimate the temperature at which its vapor pressure is 66.0 kPa.arrow_forwardDraw the structure of A, the minor E1 product of the reaction. Cl Skip Part Check F1 esc CH_CH OH, D 3 2 Click and drag to start drawing a structure. 80 R3 F4 F2 F3 @ 2 # $ 4 3 Q W 95 % KO 5 F6 A F7 × G ☐ Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ►II A A F8 F9 F10 FL 6 7 88 & * 8 9 LLI E R T Y U A S D lock LL F G H 0 P J K L Z X C V B N M 9 Harrow_forwardFrom the choices given, which two substances have the same crystal structure? (Select both) Group of answer choices ZnS (zincblende) Diamond TiO2 (rutile) ZnS (wurtzite)arrow_forward
- Potassium (K) blends with germanium (Ge) to form a Zintl phase with a chemical formula of K4Ge4. Which of the following elements would you expect potassium to blend with to form an alloy? Electronegativities: As (2.0), Cl (3.0), Ge (1.8), K (0.8), S (2.5), Ti (1.5) Group of answer choices Arsenic (As) Sulfur (S) Chlorine (Cl) Titanium (Ti)arrow_forwardConsider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forwardHow many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forward
- V Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forwardConsider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forwardWhat kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forward
- For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forwardProblem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forwardFeedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a Xarrow_forward
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