
(a)
Interpretation:
The given material
Concept introduction:
Semiconductor: A material which can conduct electricity in range between a metal and an insulator is known as semiconductor. Addition of small amount of impurities increases conductivity of semiconductor and the process is known as doping. n-type and p-type are two types of doped semiconductors.
n-type: This is a type of doped semiconductor in which many free electrons are present in conduction band.
p-type: This is a type of doped semiconductor in which holes are present in valance band.
Insulator: Insulators are one, in which electrons are filled in valence band with a vacant conduction band and they are parted away by band gap.
Conductor: Any material which can conduct electricity is known as conductor. There will be no band gap in metallic conductor and electrons can easily travel.
Figure 1
h
(b)
Semiconductor: A material which can conduct electricity in range between a metal and an insulator is known as semiconductor. Addition of small amount of impurities increases conductivity of semiconductor and the process is known as doping. n-type and p-type are two types of doped semiconductors.
n-type: This is a type of doped semiconductor in which many free electrons are present in conduction band.
p-type: This is a type of doped semiconductor in which holes are present in valance band.
Insulator: Insulators are one, in which electrons are filled in valence band with a vacant conduction band and they are parted away by band gap.
Conductor: Any material which can conduct electricity is known as conductor. There will be no band gap in metallic conductor and electrons can easily travel.
Figure 1
(c)
Interpretation:
The given material white tin has to be classified as a metallic conductor or an n-type semiconductor or a p-type semiconductor and or an insulator.
Concept introduction:
Semiconductor: A material which can conduct electricity in range between a metal and an insulator is known as semiconductor. Addition of small amount of impurities increases conductivity of semiconductor and the process is known as doping. n-type and p-type are two types of doped semiconductors.
n-type: This is a type of doped semiconductor in which many free electrons are present in conduction band.
p-type: This is a type of doped semiconductor in which holes are present in valance band.
Insulator: Insulators are one, in which electrons are filled in valence band with a vacant conduction band and they are parted away by band gap.
Conductor: Any material which can conduct electricity is known as conductor. There will be no band gap in metallic conductor and electrons can easily travel.
Figure 1
(d)
Interpretation:
The given material germanium doped with gallium has to be classified as a metallic conductor or an n-type semiconductor or a p-type semiconductor and or an insulator.
Concept introduction:
Semiconductor: A material which can conduct electricity in range between a metal and an insulator is known as semiconductor. Addition of small amount of impurities increases conductivity of semiconductor and the process is known as doping. n-type and p-type are two types of doped semiconductors.
n-type: This is a type of doped semiconductor in which many free electrons are present in conduction band.
p-type: This is a type of doped semiconductor in which holes are present in valance band.
Insulator: Insulators are one, in which electrons are filled in valence band with a vacant conduction band and they are parted away by band gap.
Conductor: Any material which can conduct electricity is known as conductor. There will be no band gap in metallic conductor and electrons can easily travel.
Figure 1
(e)
Interpretation:
The given material stainless steel has to be classified as a metallic conductor or an n-type semiconductor or a p-type semiconductor and or an insulator.
Concept introduction:
Semiconductor: A material which can conduct electricity in range between a metal and an insulator is known as semiconductor. Addition of small amount of impurities increases conductivity of semiconductor and the process is known as doping. n-type and p-type are two types of doped semiconductors.
n-type: This is a type of doped semiconductor in which many free electrons are present in conduction band.
p-type: This is a type of doped semiconductor in which holes are present in conduction band.
Insulator: Insulators are one, in which electrons are filled in valence band with a vacant conduction band and they are parted away by band gap.
Conductor: Any material which can conduct electricity is known as conductor. There will be no band gap in metallic conductor and electrons can easily travel.
Figure 1

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Chapter 21 Solutions
General Chemistry: Atoms First
- i need help with the followingarrow_forwardUsing reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NO(g) +Cl₂ (g) = 2NOC1 (g) AGº = -41. kJ Now suppose a reaction vessel is filled with 8.90 atm of chlorine (C12) and 5.71 atm of nitrosyl chloride (NOC1) at 1075. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. atm ☑ 18 Ararrow_forwardIdentifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCN is a weak acid. acids: 0.29 mol of NaOH is added to 1.0 L of a 1.2M HCN solution. bases: ☑ other: 0.09 mol of HCl is added to acids: 1.0 L of a solution that is bases: 0.3M in both HCN and KCN. other: 0,0,... ? 00. 18 Ar 日arrow_forward
- Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 0.2 mol of KOH is added to 1.0 L of a 0.5 M HF solution. bases: Х other: ☐ acids: 0.10 mol of HI is added to 1.0 L of a solution that is 1.4M in both HF and NaF. bases: other: ☐ 0,0,... ด ? 18 Ararrow_forwardIdentifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that NH3 is a weak base. acids: ☐ 1.8 mol of HCl is added to 1.0 L of a 1.0M NH3 bases: ☐ solution. other: ☐ 0.18 mol of HNO3 is added to 1.0 L of a solution that is 1.4M in both NH3 and NH₁Br. acids: bases: ☐ other: ☐ 0,0,... ? 000 18 Ar B 1arrow_forwardUsing reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NH3 (g) = N2 (g) +3H₂ —N2 (g) AGº = 34. kJ Now suppose a reaction vessel is filled with 4.19 atm of ammonia (NH3) and 9.94 atm of nitrogen (N2) at 378. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of NH 3 tend to rise or fall? ☐ x10 fall Х Is it possible to reverse this tendency by adding H₂? In other words, if you said the pressure of NH 3 will tend to rise, can that be changed to a tendency to fall by adding H₂? Similarly, if you said the pressure of NH3 will tend to fall, can that be changed to a tendency to rise by adding H₂? If you said the tendency can be reversed in the second question, calculate the minimum pressure of H₂ needed to reverse it. Round your answer to 2 significant digits. yes no atm 00. 18 Ar 무ㅎ ?arrow_forward
- Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. 2.2 mol of NaOH is added to 1.0 L of a 1.4M HF solution. acids: П bases: Х other: ☐ ப acids: 0.51 mol of KOH is added to 1.0 L of a solution that is bases: 1.3M in both HF and NaF. other: ☐ 00. 18 Ararrow_forwardUsing reaction free energy to predict equilibrium composition Consider the following equilibrium: N2O4 (g) 2NO2 (g) AG⁰ = 5.4 kJ Now suppose a reaction vessel is filled with 1.68 atm of dinitrogen tetroxide (N204) at 148. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of N2O4 tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO2? In other words, if you said the pressure of N2O4 will tend to rise, can that be changed to a tendency to fall by adding NO2? Similarly, if you said the pressure of N2O4 will tend to fall, can that be changed to a tendency to rise by adding NO2? If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO 2 needed to reverse it. Round your answer to 2 significant digits. yes no 0.42 atm ☑ 5 0/5 ? مله Ararrow_forwardHomework 13 (Ch17) Question 4 of 4 (1 point) | Question Attempt: 2 of 2 ✓ 1 ✓ 2 = 3 4 Time Remaining: 4:25:54 Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction: 2CH3OH (g)+302 (g) → 2CO2 (g) + 4H₂O (g) Round your answer to zero decimal places. ☐ kJ x10 ☐ Subm Check 2020 Hill LLC. All Rights Reserved. Terms of Use | Privacy Cearrow_forward
- Identifying the major species in weak acid or weak base equilibria Your answer is incorrect. • Row 2: Your answer is incorrect. • Row 3: Your answer is incorrect. • Row 6: Your answer is incorrect. 0/5 The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: HF 0.1 mol of NaOH is added to 1.0 L of a 0.7M HF solution. bases: 0.13 mol of HCl is added to 1.0 L of a solution that is 1.0M in both HF and KF. Exponent other: F acids: HF bases: F other: K 1 0,0,... ? 000 18 Ararrow_forwardUsing reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NOCI (g) 2NO (g) + Cl2 (g) AGº =41. kJ Now suppose a reaction vessel is filled with 4.50 atm of nitrosyl chloride (NOCI) and 6.38 atm of chlorine (C12) at 212. °C. Answer the following questions about this system: ? rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. 0.035 atm ✓ G 00. 18 Ararrow_forwardHighlight each glycosidic bond in the molecule below. Then answer the questions in the table under the drawing area. HO- HO- -0 OH OH HO NG HO- HO- OH OH OH OH NG OHarrow_forward
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