
General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Question
Chapter 21, Problem 21.32SP
Interpretation Introduction
Interpretation:
The reason for roasting of sphalerite yields zinc oxide whereas cinnabar gives elemental mercury has to be explained. Also the product of roasting of cadmium sulfide has to be identified.
Concept introduction:
- Reduction of an ore can be done by chemical reduction or
electrolysis . - It depends on metal activity which is determined by standard reduction potential of metals.
- The most active metals are hard to reduce because of its negative standard reduction potential.
- The least active metals are easy to reduce because of its positive standard reduction potential.
- A table defines reduction methods of various metal ores is given as follows
Figure 1
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Chapter 21 Solutions
General Chemistry: Atoms First
Ch. 21.1 - In view of the 3charge on the PO43 ion, explain...Ch. 21.2 - Prob. 21.2PCh. 21.3 - Prob. 21.3PCh. 21.4 - Prob. 21.4PCh. 21.4 - Prob. 21.5CPCh. 21.5 - Prob. 21.6PCh. 21.5 - Prob. 21.7CPCh. 21.6 - Prob. 21.8PCh. 21.7 - Show that one unit cell of YBa2Cu3O7 (Figure...Ch. 21.8 - Prob. 21.10P
Ch. 21.8 - Prob. 21.11PCh. 21.9 - Prob. 21.12PCh. 21.9 - Prob. 21.13PCh. 21.9 - Prob. 21.14PCh. 21 - Prob. 21.15CPCh. 21 - Prob. 21.16CPCh. 21 - Prob. 21.17CPCh. 21 - Prob. 21.18CPCh. 21 - Prob. 21.19CPCh. 21 - Prob. 21.20CPCh. 21 - Prob. 21.21CPCh. 21 - Prob. 21.22SPCh. 21 - Prob. 21.23SPCh. 21 - Prob. 21.24SPCh. 21 - Prob. 21.25SPCh. 21 - Prob. 21.26SPCh. 21 - Prob. 21.27SPCh. 21 - Prob. 21.28SPCh. 21 - Prob. 21.29SPCh. 21 - Prob. 21.30SPCh. 21 - Prob. 21.31SPCh. 21 - Prob. 21.32SPCh. 21 - Prob. 21.33SPCh. 21 - Prob. 21.34SPCh. 21 - Prob. 21.35SPCh. 21 - Prob. 21.36SPCh. 21 - Prob. 21.37SPCh. 21 - Prob. 21.38SPCh. 21 - Prob. 21.39SPCh. 21 - Prob. 21.40SPCh. 21 - Prob. 21.41SPCh. 21 - Prob. 21.42SPCh. 21 - Prob. 21.43SPCh. 21 - Prob. 21.44SPCh. 21 - Prob. 21.45SPCh. 21 - Prob. 21.46SPCh. 21 - Prob. 21.47SPCh. 21 - Prob. 21.48SPCh. 21 - Prob. 21.49SPCh. 21 - Prob. 21.50SPCh. 21 - Prob. 21.51SPCh. 21 - Prob. 21.52SPCh. 21 - Prob. 21.53SPCh. 21 - Prob. 21.54SPCh. 21 - Prob. 21.55SPCh. 21 - Prob. 21.56SPCh. 21 - Prob. 21.57SPCh. 21 - Prob. 21.58SPCh. 21 - Prob. 21.59SPCh. 21 - Prob. 21.60SPCh. 21 - Prob. 21.61SPCh. 21 - Prob. 21.62SPCh. 21 - Prob. 21.63SPCh. 21 - Prob. 21.64SPCh. 21 - Prob. 21.65SPCh. 21 - Prob. 21.66SPCh. 21 - Prob. 21.67SPCh. 21 - Prob. 21.68SPCh. 21 - Prob. 21.69SPCh. 21 - Prob. 21.70SPCh. 21 - Prob. 21.71SPCh. 21 - Prob. 21.72SPCh. 21 - Prob. 21.73SPCh. 21 - Prob. 21.74SPCh. 21 - Prob. 21.75SPCh. 21 - Prob. 21.76SPCh. 21 - Prob. 21.77SPCh. 21 - Prob. 21.78SPCh. 21 - Prob. 21.79SPCh. 21 - Prob. 21.80SPCh. 21 - Prob. 21.81SPCh. 21 - Prob. 21.82SPCh. 21 - Prob. 21.83SPCh. 21 - Prob. 21.84SPCh. 21 - Prob. 21.85SPCh. 21 - Prob. 21.86SPCh. 21 - Prob. 21.87SPCh. 21 - Prob. 21.88SPCh. 21 - Prob. 21.89SPCh. 21 - Prob. 21.90SPCh. 21 - Prob. 21.92SPCh. 21 - Prob. 21.93SPCh. 21 - Prob. 21.94SPCh. 21 - Prob. 21.95SPCh. 21 - Prob. 21.96SPCh. 21 - Prob. 21.97SPCh. 21 - Prob. 21.98SPCh. 21 - Prob. 21.99SPCh. 21 - Prob. 21.100SPCh. 21 - Prob. 21.101SPCh. 21 - Prob. 21.102SPCh. 21 - Prob. 21.103SPCh. 21 - Prob. 21.104SPCh. 21 - Prob. 21.105SPCh. 21 - Prob. 21.106SPCh. 21 - Prob. 21.107SPCh. 21 - Prob. 21.108SPCh. 21 - Prob. 21.109SPCh. 21 - Prob. 21.110CHPCh. 21 - Prob. 21.111CHPCh. 21 - Prob. 21.112CHPCh. 21 - Prob. 21.113CHPCh. 21 - Prob. 21.114CHPCh. 21 - Prob. 21.115CHPCh. 21 - Prob. 21.116CHPCh. 21 - Prob. 21.117CHPCh. 21 - Prob. 21.118CHPCh. 21 - Prob. 21.119CHPCh. 21 - Prob. 21.120CHPCh. 21 - Prob. 21.121CHPCh. 21 - Prob. 21.122CHPCh. 21 - Prob. 21.123CHPCh. 21 - Prob. 21.124CHPCh. 21 - Prob. 21.125CHPCh. 21 - Prob. 21.127CHPCh. 21 - Prob. 21.128CHPCh. 21 - Prob. 21.129CHPCh. 21 - Prob. 21.130MPCh. 21 - Prob. 21.131MPCh. 21 - Prob. 21.132MPCh. 21 - Prob. 21.133MPCh. 21 - Prob. 21.134MPCh. 21 - At high temperatures, coke reduces silica...Ch. 21 - Prob. 21.136MPCh. 21 - Zinc chromite (ZnCr2O4), once used to make...Ch. 21 - Prob. 21.140MP
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- Propose a synthesis of 1-butanamine from the following: (a) a chloroalkane of three carbons (b) a chloroalkane of four carbonsarrow_forwardSelect the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forward
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- Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forwardInstructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forward
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