General Chemistry: Atoms First
General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Chapter 21, Problem 21.136MP

(a)

Interpretation Introduction

Interpretation:

ΔGo and equilibrium constant Kp at 150oC has to be calculated.

Concept introduction:

  • Mond process is a method in which volatile compound nickel tetracarbonyl Ni(CO)4 is formed and subsequently decomposed.

Ni(s)+4CO(g)Ni(CO)4(g), where ΔHo=160.8kJΔSo=410J/K

  • ΔGo=ΔHoTΔSo , where ΔGo, the change in standard Gibbs free energy , ΔHo is the change in standard enthalpy ΔSo is the change in standard entropy and T is the temperature in kelvin.
  • ΔGo=RTlnKp where ΔGo, the change in standard Gibbs free energy, R is the universal gas constant 8.314J and Kp is the equilibrium constant.

(b)

Interpretation Introduction

Interpretation:

ΔGo and equilibrium constant Kp at 230oC has to be calculated.

Concept introduction:

  • Mond process is a method in which volatile compound nickel tetracarbonyl Ni(CO)4 is formed and subsequently decomposed.

Ni(s)+4CO(g)Ni(CO)4(g), where ΔHo=160.8kJΔSo=410J/K

  • ΔGo=ΔHoTΔSo , where ΔGo, the change in standard Gibbs free energy , ΔHo is the change in standard enthalpy ΔSo is the change in standard entropy and T is the temperature in kelvin.
  • ΔGo=RTlnKp where ΔGo, the change in standard Gibbs free energy, R is the universal gas constant 8.314J and Kp is the equilibrium constant.

(c)

Interpretation Introduction

Interpretation:

Reason for large negative value in for ΔSo and also the change in ΔGo with temperature is consistent with the negative value of ΔSo has to be explained.

Concept introduction:

  • Mond process is a method in which volatile compound nickel tetracarbonyl Ni(CO)4 is formed and subsequently decomposed.

Ni(s)+4CO(g)Ni(CO)4(g), where ΔHo=160.8kJΔSo=410J/K

  • ΔGo=ΔHoTΔSo , where ΔGo, the change in standard Gibbs free energy, ΔHo is the change in standard enthalpy ΔSo is the change in standard entropy and T is the temperature in kelvin.
  • ΔGo=RTlnKp, where ΔGo, the change in standard Gibbs free energy, R is the universal gas constant 8.314J and Kp is the equilibrium constant.

(d)

Interpretation Introduction

Interpretation:

The change in Kp with increasing temperature is consistent with the negative value of ΔHo has to be explained.

Concept introduction:

  • Mond process is a method in which volatile compound nickel tetracarbonyl Ni(CO)4 is formed and subsequently decomposed.

Ni(s)+4CO(g)Ni(CO)4(g), where ΔHo=160.8kJΔSo=410J/K

  • ΔGo=ΔHoTΔSo , where ΔGo, the change in standard Gibbs free energy, ΔHo is the change in standard enthalpy ΔSo is the change in standard entropy and T is the temperature in kelvin.
  • ΔGo=RTlnKp, where ΔGo, the change in standard Gibbs free energy, R is the universal gas constant 8.314J and Kp is the equilibrium constant.

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Chapter 21 Solutions

General Chemistry: Atoms First

Ch. 21.8 - Prob. 21.11PCh. 21.9 - Prob. 21.12PCh. 21.9 - Prob. 21.13PCh. 21.9 - Prob. 21.14PCh. 21 - Prob. 21.15CPCh. 21 - Prob. 21.16CPCh. 21 - Prob. 21.17CPCh. 21 - Prob. 21.18CPCh. 21 - Prob. 21.19CPCh. 21 - Prob. 21.20CPCh. 21 - Prob. 21.21CPCh. 21 - Prob. 21.22SPCh. 21 - Prob. 21.23SPCh. 21 - Prob. 21.24SPCh. 21 - Prob. 21.25SPCh. 21 - Prob. 21.26SPCh. 21 - Prob. 21.27SPCh. 21 - Prob. 21.28SPCh. 21 - Prob. 21.29SPCh. 21 - Prob. 21.30SPCh. 21 - Prob. 21.31SPCh. 21 - Prob. 21.32SPCh. 21 - Prob. 21.33SPCh. 21 - Prob. 21.34SPCh. 21 - Prob. 21.35SPCh. 21 - Prob. 21.36SPCh. 21 - Prob. 21.37SPCh. 21 - Prob. 21.38SPCh. 21 - Prob. 21.39SPCh. 21 - Prob. 21.40SPCh. 21 - Prob. 21.41SPCh. 21 - Prob. 21.42SPCh. 21 - Prob. 21.43SPCh. 21 - Prob. 21.44SPCh. 21 - Prob. 21.45SPCh. 21 - Prob. 21.46SPCh. 21 - Prob. 21.47SPCh. 21 - Prob. 21.48SPCh. 21 - Prob. 21.49SPCh. 21 - Prob. 21.50SPCh. 21 - Prob. 21.51SPCh. 21 - Prob. 21.52SPCh. 21 - Prob. 21.53SPCh. 21 - Prob. 21.54SPCh. 21 - Prob. 21.55SPCh. 21 - Prob. 21.56SPCh. 21 - Prob. 21.57SPCh. 21 - Prob. 21.58SPCh. 21 - Prob. 21.59SPCh. 21 - Prob. 21.60SPCh. 21 - Prob. 21.61SPCh. 21 - Prob. 21.62SPCh. 21 - Prob. 21.63SPCh. 21 - Prob. 21.64SPCh. 21 - Prob. 21.65SPCh. 21 - Prob. 21.66SPCh. 21 - Prob. 21.67SPCh. 21 - Prob. 21.68SPCh. 21 - Prob. 21.69SPCh. 21 - Prob. 21.70SPCh. 21 - Prob. 21.71SPCh. 21 - Prob. 21.72SPCh. 21 - Prob. 21.73SPCh. 21 - Prob. 21.74SPCh. 21 - Prob. 21.75SPCh. 21 - Prob. 21.76SPCh. 21 - Prob. 21.77SPCh. 21 - Prob. 21.78SPCh. 21 - Prob. 21.79SPCh. 21 - Prob. 21.80SPCh. 21 - Prob. 21.81SPCh. 21 - Prob. 21.82SPCh. 21 - Prob. 21.83SPCh. 21 - Prob. 21.84SPCh. 21 - Prob. 21.85SPCh. 21 - Prob. 21.86SPCh. 21 - Prob. 21.87SPCh. 21 - Prob. 21.88SPCh. 21 - Prob. 21.89SPCh. 21 - Prob. 21.90SPCh. 21 - Prob. 21.92SPCh. 21 - Prob. 21.93SPCh. 21 - Prob. 21.94SPCh. 21 - Prob. 21.95SPCh. 21 - Prob. 21.96SPCh. 21 - Prob. 21.97SPCh. 21 - Prob. 21.98SPCh. 21 - Prob. 21.99SPCh. 21 - Prob. 21.100SPCh. 21 - Prob. 21.101SPCh. 21 - Prob. 21.102SPCh. 21 - Prob. 21.103SPCh. 21 - Prob. 21.104SPCh. 21 - Prob. 21.105SPCh. 21 - Prob. 21.106SPCh. 21 - Prob. 21.107SPCh. 21 - Prob. 21.108SPCh. 21 - Prob. 21.109SPCh. 21 - Prob. 21.110CHPCh. 21 - Prob. 21.111CHPCh. 21 - Prob. 21.112CHPCh. 21 - Prob. 21.113CHPCh. 21 - Prob. 21.114CHPCh. 21 - Prob. 21.115CHPCh. 21 - Prob. 21.116CHPCh. 21 - Prob. 21.117CHPCh. 21 - Prob. 21.118CHPCh. 21 - Prob. 21.119CHPCh. 21 - Prob. 21.120CHPCh. 21 - Prob. 21.121CHPCh. 21 - Prob. 21.122CHPCh. 21 - Prob. 21.123CHPCh. 21 - Prob. 21.124CHPCh. 21 - Prob. 21.125CHPCh. 21 - Prob. 21.127CHPCh. 21 - Prob. 21.128CHPCh. 21 - Prob. 21.129CHPCh. 21 - Prob. 21.130MPCh. 21 - Prob. 21.131MPCh. 21 - Prob. 21.132MPCh. 21 - Prob. 21.133MPCh. 21 - Prob. 21.134MPCh. 21 - At high temperatures, coke reduces silica...Ch. 21 - Prob. 21.136MPCh. 21 - Zinc chromite (ZnCr2O4), once used to make...Ch. 21 - Prob. 21.140MP
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