General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Question
Chapter 21, Problem 21.39SP
(a)
Interpretation Introduction
Interpretation:
The amount of
(b)
Interpretation Introduction
Interpretation:
At STP, the number of liters of
(c)
Interpretation Introduction
Interpretation:
The amount of sulfuric acid obtained when
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Hematite, Fe203, is an important ore of iron. (An ore is a natural
substance from which the metal can be profitably obtained.) The free
metal is obtained by reacting hematite with carbon monoxide, CO, in a
blast furnace. Carbon monoxide is formed in the furnace by partial
combustion of carbon. The reaction is
Fe203(s) + 3CO(g) → 2Fe(s) + 3CO2(g)
How many grams of iron can be produced from 1.17 kg Fe203?
g Fe
In a blast furnace, coke, which is solid carbon, reacts with O2(g) to form carbon monoxide. The carbon monoxide then reacts with Fe2O3(s) to produce solid iron and carbon dioxide. Which of the following is the
balanced equation for this combined process?
O2 Fe2O3(s) + 3 C(s) + 3 02(g)->2 Fe(s) + 3 CO2(g)
O2 Fe2O3(s) + 2 C(s) + 3 02(g)-> 4 Fe(s) + 2 CO2(g)
O2 Fe2O3(s) + 6 C(s) + 3 02(g)--> 4 Fe(s) + 6 CO2(g)
O2 Fe2O3(s) + C(s) + 3 O2(g) -> Fe(s) + CO2(g)
(1) One of the steps in the commercial process for converting ammonia to nitric acid involves the conversion of ammonia, NH3(g) to nitrous oxide, NO(g).
4 NH3(g ) + 5 O2(g) → 4 NO(g) + 6 H2O(l)
Atomic weights (g/mol): N=14, H=1, O=16
a. Balance the above chemical equation that represents the conversion.
b. How many moles of oxygen are needed to convert 2.5 moles of ammonia?
c. How many grams of water will be produced from 2.5 moles of ammonia?
d. If 150 grams of oxygen reacted 2.5 moles of ammonia, identify the limiting and excess reagents.
e. How much of the excess reagent remains unreacted?
f. If the reaction in (d) produces 10.0 grams of nitrous oxide, calculate the percent yield.
Chapter 21 Solutions
General Chemistry: Atoms First
Ch. 21.1 - In view of the 3charge on the PO43 ion, explain...Ch. 21.2 - Prob. 21.2PCh. 21.3 - Prob. 21.3PCh. 21.4 - Prob. 21.4PCh. 21.4 - Prob. 21.5CPCh. 21.5 - Prob. 21.6PCh. 21.5 - Prob. 21.7CPCh. 21.6 - Prob. 21.8PCh. 21.7 - Show that one unit cell of YBa2Cu3O7 (Figure...Ch. 21.8 - Prob. 21.10P
Ch. 21.8 - Prob. 21.11PCh. 21.9 - Prob. 21.12PCh. 21.9 - Prob. 21.13PCh. 21.9 - Prob. 21.14PCh. 21 - Prob. 21.15CPCh. 21 - Prob. 21.16CPCh. 21 - Prob. 21.17CPCh. 21 - Prob. 21.18CPCh. 21 - Prob. 21.19CPCh. 21 - Prob. 21.20CPCh. 21 - Prob. 21.21CPCh. 21 - Prob. 21.22SPCh. 21 - Prob. 21.23SPCh. 21 - Prob. 21.24SPCh. 21 - Prob. 21.25SPCh. 21 - Prob. 21.26SPCh. 21 - Prob. 21.27SPCh. 21 - Prob. 21.28SPCh. 21 - Prob. 21.29SPCh. 21 - Prob. 21.30SPCh. 21 - Prob. 21.31SPCh. 21 - Prob. 21.32SPCh. 21 - Prob. 21.33SPCh. 21 - Prob. 21.34SPCh. 21 - Prob. 21.35SPCh. 21 - Prob. 21.36SPCh. 21 - Prob. 21.37SPCh. 21 - Prob. 21.38SPCh. 21 - Prob. 21.39SPCh. 21 - Prob. 21.40SPCh. 21 - Prob. 21.41SPCh. 21 - Prob. 21.42SPCh. 21 - Prob. 21.43SPCh. 21 - Prob. 21.44SPCh. 21 - Prob. 21.45SPCh. 21 - Prob. 21.46SPCh. 21 - Prob. 21.47SPCh. 21 - Prob. 21.48SPCh. 21 - Prob. 21.49SPCh. 21 - Prob. 21.50SPCh. 21 - Prob. 21.51SPCh. 21 - Prob. 21.52SPCh. 21 - Prob. 21.53SPCh. 21 - Prob. 21.54SPCh. 21 - Prob. 21.55SPCh. 21 - Prob. 21.56SPCh. 21 - Prob. 21.57SPCh. 21 - Prob. 21.58SPCh. 21 - Prob. 21.59SPCh. 21 - Prob. 21.60SPCh. 21 - Prob. 21.61SPCh. 21 - Prob. 21.62SPCh. 21 - Prob. 21.63SPCh. 21 - Prob. 21.64SPCh. 21 - Prob. 21.65SPCh. 21 - Prob. 21.66SPCh. 21 - Prob. 21.67SPCh. 21 - Prob. 21.68SPCh. 21 - Prob. 21.69SPCh. 21 - Prob. 21.70SPCh. 21 - Prob. 21.71SPCh. 21 - Prob. 21.72SPCh. 21 - Prob. 21.73SPCh. 21 - Prob. 21.74SPCh. 21 - Prob. 21.75SPCh. 21 - Prob. 21.76SPCh. 21 - Prob. 21.77SPCh. 21 - Prob. 21.78SPCh. 21 - Prob. 21.79SPCh. 21 - Prob. 21.80SPCh. 21 - Prob. 21.81SPCh. 21 - Prob. 21.82SPCh. 21 - Prob. 21.83SPCh. 21 - Prob. 21.84SPCh. 21 - Prob. 21.85SPCh. 21 - Prob. 21.86SPCh. 21 - Prob. 21.87SPCh. 21 - Prob. 21.88SPCh. 21 - Prob. 21.89SPCh. 21 - Prob. 21.90SPCh. 21 - Prob. 21.92SPCh. 21 - Prob. 21.93SPCh. 21 - Prob. 21.94SPCh. 21 - Prob. 21.95SPCh. 21 - Prob. 21.96SPCh. 21 - Prob. 21.97SPCh. 21 - Prob. 21.98SPCh. 21 - Prob. 21.99SPCh. 21 - Prob. 21.100SPCh. 21 - Prob. 21.101SPCh. 21 - Prob. 21.102SPCh. 21 - Prob. 21.103SPCh. 21 - Prob. 21.104SPCh. 21 - Prob. 21.105SPCh. 21 - Prob. 21.106SPCh. 21 - Prob. 21.107SPCh. 21 - Prob. 21.108SPCh. 21 - Prob. 21.109SPCh. 21 - Prob. 21.110CHPCh. 21 - Prob. 21.111CHPCh. 21 - Prob. 21.112CHPCh. 21 - Prob. 21.113CHPCh. 21 - Prob. 21.114CHPCh. 21 - Prob. 21.115CHPCh. 21 - Prob. 21.116CHPCh. 21 - Prob. 21.117CHPCh. 21 - Prob. 21.118CHPCh. 21 - Prob. 21.119CHPCh. 21 - Prob. 21.120CHPCh. 21 - Prob. 21.121CHPCh. 21 - Prob. 21.122CHPCh. 21 - Prob. 21.123CHPCh. 21 - Prob. 21.124CHPCh. 21 - Prob. 21.125CHPCh. 21 - Prob. 21.127CHPCh. 21 - Prob. 21.128CHPCh. 21 - Prob. 21.129CHPCh. 21 - Prob. 21.130MPCh. 21 - Prob. 21.131MPCh. 21 - Prob. 21.132MPCh. 21 - Prob. 21.133MPCh. 21 - Prob. 21.134MPCh. 21 - At high temperatures, coke reduces silica...Ch. 21 - Prob. 21.136MPCh. 21 - Zinc chromite (ZnCr2O4), once used to make...Ch. 21 - Prob. 21.140MP
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