Introduction To Quantum Mechanics
3rd Edition
ISBN: 9781107189638
Author: Griffiths, David J., Schroeter, Darrell F.
Publisher: Cambridge University Press
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Question
Chapter 2, Problem 2.46P
To determine
The allowed energies corresponding to the stationary states and the basis for degeneracy.
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Learning Goal:
To understand the meaning and the basic applications of
pV diagrams for an ideal gas.
As you know, the parameters of an ideal gas are
described by the equation
pV = nRT,
where p is the pressure of the gas, V is the volume of
the gas, n is the number of moles, R is the universal gas
constant, and T is the absolute temperature of the gas. It
follows that, for a portion of an ideal gas,
PV
T
=
constant.
One can see that, if the amount of gas remains constant,
it is impossible to change just one parameter of the gas:
At least one more parameter would also change. For
instance, if the pressure of the gas is changed, we can
be sure that either the volume or the temperature of the
gas (or, maybe, both!) would also change.
To explore these changes, it is often convenient to draw a
graph showing one parameter as a function of the other.
Although there are many choices of axes, the most
common one is a plot of pressure as a function of
volume: a pV diagram.
In this problem, you…
A-e please
Two moles of carbon monoxide (CO) start at a pressure of 1.4 atm and a volume of 35 liters. The gas is then
compressed adiabatically to 1/3 this volume. Assume that the gas may be treated as ideal.
Part A
What is the change in the internal energy of the gas?
Express your answer using two significant figures.
ΕΠΙ ΑΣΦ
AU =
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Part B
Does the internal energy increase or decrease?
internal energy increases
internal energy decreases
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Part C
?
J
Does the temperature of the gas increase or decrease during this process?
temperature of the gas increases
temperature of the gas decreases
Submit
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Chapter 2 Solutions
Introduction To Quantum Mechanics
Ch. 2.1 - Prob. 2.1PCh. 2.1 - Prob. 2.2PCh. 2.2 - Prob. 2.3PCh. 2.2 - Prob. 2.4PCh. 2.2 - Prob. 2.5PCh. 2.2 - Prob. 2.6PCh. 2.2 - Prob. 2.7PCh. 2.2 - Prob. 2.8PCh. 2.2 - Prob. 2.9PCh. 2.3 - Prob. 2.10P
Ch. 2.3 - Prob. 2.11PCh. 2.3 - Prob. 2.12PCh. 2.3 - Prob. 2.13PCh. 2.3 - Prob. 2.14PCh. 2.3 - Prob. 2.15PCh. 2.3 - Prob. 2.16PCh. 2.4 - Prob. 2.17PCh. 2.4 - Prob. 2.18PCh. 2.4 - Prob. 2.19PCh. 2.4 - Prob. 2.20PCh. 2.4 - Prob. 2.21PCh. 2.5 - Prob. 2.22PCh. 2.5 - Prob. 2.23PCh. 2.5 - Prob. 2.24PCh. 2.5 - Prob. 2.25PCh. 2.5 - Prob. 2.26PCh. 2.5 - Prob. 2.27PCh. 2.5 - Prob. 2.28PCh. 2.6 - Prob. 2.29PCh. 2.6 - Prob. 2.30PCh. 2.6 - Prob. 2.31PCh. 2.6 - Prob. 2.32PCh. 2.6 - Prob. 2.34PCh. 2.6 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64P
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