The power triangle.

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In a railway system with a power source of 600 VDC, I need to achieve a load output of 120 VDC for railway lights. I found a DC-DC converter capable of stepping down 600 VDC to 125 VDC. To obtain 120 VDC from this converter, we can use a voltage divider with the following equation: [R2/(R2+R1)]=120/125=0.96=0.96However, using resistors to achieve the desired output voltage raises some concerns. Is it advisable to use railway-grade resistors for this application? I found some resistors in the range of 1-10k ohms, but I am unsure how they should be connected in the circuit with the lights (the load to be used). I would greatly appreciate any suggestions or schematic diagrams to clarify the best approach for connecting the resistors in this setup.

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Chapter 2, Problem 2.41P

To determine

The power triangle.

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