Chapter 2, Problem 100A

(a)

Interpretation Introduction

Interpretation:

The given quantity 3.01 g needs to be converted to cg unit.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 100A

3.01 g is equal to 310 cg.

Explanation of Solution

Since, $1\text{g}=100\text{cg}$

Then,

$\begin{array}{c}3.01\text{g}=3.01\times 100\text{cg}\\ =301\text{cg}\end{array}$

(b)

Interpretation Introduction

Interpretation:

The given quantity 6200 m needs to be converted to km unit.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 100A

6200 m is equal to 6.2 km.

Explanation of Solution

Since, $1\text{m}=0.\text{001}\text{km}$

Then,

$\begin{array}{c}6200\text{m}=6200\times 0.001\text{km}\\ =6.2\text{km}\end{array}$

(c)

Interpretation Introduction

Interpretation:

The given quantity $6.24\times {10}^{-7}\text{g}$ needs to be converted to $\text{μg}$ unit.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 100A

$6.24\times {10}^{-7}\text{g}$ is equal to $0.624\text{μg}$.

Explanation of Solution

Since, $1\text{g}=1000000\text{μg}$

Then,

$\begin{array}{c}6.24\times {10}^{-7}\text{g}=6.24\times {10}^{-7}\times 1000000\text{μg}\\ \text{=}6.24\times {10}^{-7}\times {10}^6\text{μg}\\ \text{=}6.24\times {10}^{-7+6}\\ =6.24\times {10}^{-1}\\ =\frac{6.24}{10}\\ =0.624\text{μg}\end{array}$

(d)

Interpretation Introduction

Interpretation:

The given quantity 0.2 L needs to be converted to dm³ unit.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 100A

0.2 L is equal to 0.2 dm³.

Explanation of Solution

Since, $1\text{L}=1{\text{dm}}^{\text{3}}$

Then,

$\begin{array}{c}0.2\text{L}=0.2\times 1{\text{dm}}^{\text{3}}\\ =0.2{\text{dm}}^{\text{3}}\end{array}$

(e)

Interpretation Introduction

Interpretation:

The given quantity 0.13 cal/g needs to be converted into kcal/g unit.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 100A

$0.13\text{cal/g}$ is equal to $0.00013\text{kcal/g}$.

Explanation of Solution

Since, $1\text{gcal}=0.001\text{kcal}$

Then,

$\begin{array}{c}0.13\text{cal/g}=0.13\times 0.001\text{kcal/g}\\ =0.00013\text{kcal/g}\end{array}$

(f)

Interpretation Introduction

Interpretation:

The given quantity 3.21 mL needs to be converted into L unit.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 100A

3.21 mL is equal to 0.00321 L.

Explanation of Solution

Since, $1\text{mL}=0.001\text{L}$

Then,

$\begin{array}{c}3.21\text{mL}=3.21\times 0.001\text{L}\\ =0.00321\text{L}\end{array}$