Chapter 2, Problem 111A

Interpretation Introduction

Interpretation:

The slope of the graph needs to be determined by plotting volume and mass on x-axis and y-axis respectively from the given data.

Concept introduction:

For a straight line, the equation of graph is as follows:

$y=mx+c$

Here, m is slope of the graph and c is intercept of the graph plotted between x and y variables.

Answer to Problem 111A

Given information:

Data is recorded in the table as:

Density Data
Volume (mL)	Mass (g)
2.0	5.4
4.0	10.8
6.0	16.2
8.0	21.6
9.0	27.0

Calculation:

The graph from the data give is as:

The slope of the graph is 0.3704.

Explanation of Solution

From the data given, the graph will be:

Now, for the determination of the slope, divide the difference of the two points on x-axis by the difference of the two points on y-axis. The two values on the x-axis to be used are 4.0 mL and 2.0 mL. Two values on the y-axis to be used are 10.8 g and 5.4 g. the slope will be we equal to the mass divided by volume here.

$\begin{array}{c}\text{Slope}=\frac{x_2-x_1}{y_2-y_1}\\ =\frac{4.0-2.0}{10.8-5.4}\\ =\frac{2.0}{5.4}\\ =0.3704\end{array}$

Hence, the slope of the graph will be 0.3704.

Conclusion

The graph from the data give is as:

The slope of the graph is 0.3704.