Chapter 1.9, Problem 35E

To determine

To calculate: The value of $x$ from the equation $x^2-32=0$ by algebraic method and graphical method.

Answer to Problem 35E

The value of $x$ is $\pm \sqrt{32}$ and Graph of the equation is provided below,

  

Explanation of Solution

Given information:

The equation $x^2-32=0$ .

Calculation:

It is provided that the equation $x^2-32=0$ .

Algebraic method;

The method in which isolate $x$ on one side of the equation and solve the value of $x$ .

From the equation $x^2-32=0$ ,

Add 32 on the both side of the equation $x^2-32=0$

  $x^2=32$

Solve the value of $x$ from the equation,

  $\begin{array}{l}{x}^2=32\\ x=\pm \sqrt{32}\end{array}$

Therefore, the value of $x=\pm \sqrt{32}$ .

Graphical method;

The graph of the equation $x=+\sqrt{32}$ provided below,

  

The graph of equation $x=-\sqrt{32}$ is provided below,

  

The graph of both equations in same figure is provided below,

  

The solution is the $x$ coordinate of the intersection point of the two graphs. So, there is no intersection points on the $x$ coordinate.