
(a)
To find: The center and radius of circle
(a)

Answer to Problem 18T
The center of circle is
Explanation of Solution
Section1:
The given equation of circle is
The equation of circle with center
Rewrite the given equation,
Compare above equation with equation (1) to get the center
Thus, the center of circle is
Section2:
From the section1 the center of circle is pass through origin and the radius of circle is 5 that is shown below,
Figure (1)
Figure (1) shows the graph of circle
(b)
To find: The center and radius of circle
(b)

Answer to Problem 18T
The center of circle is
Explanation of Solution
Section1:
The given equation of circle is
The equation of circle with center
Rewrite the given equation,
Compare given equation with above equation to get the center
Thus, the center of circle is
Section2:
The given equation of circle is
From the section1 the center of circle is
Figure (2)
Figure (2) shows the graph of circle
(c)
To find: The center and radius of circle
(c)

Answer to Problem 18T
The center of circle is
Explanation of Solution
Given:
The equation is
Calculation:
Section1:
The equation of circle with center
First, group the x-terms and y-terms then make a complete square within each group in the given equation,
Add
Compare the above equation with equation (1) to get the center
Thus, the center of circle is
Section2:
From the section1 the center of circle is
Figure (3)
Figure (3) shows the graph of circle
Chapter 1 Solutions
EBK PRECALCULUS: MATHEMATICS FOR CALCUL
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- review help please and thank you!arrow_forward(10 points) Let S be the surface that is part of the sphere x² + y²+z² = 4 lying below the plane 2√3 and above the plane z-v -√3. Calculate the surface area of S.arrow_forward(8 points) Let D = {(x, y) | 0 ≤ x² + y² ≤4}. Calculate == (x² + y²)³/2dA by making a change of variables to polar coordinates, i.e. x=rcos 0, y = r sin 0.arrow_forward
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