To show: The equation
Answer to Problem 103E
The equation
Explanation of Solution
Given information:
The equation
Formula used:
In order to solve a quadratic equation, completing the square method is used that transforms the equation in the form of square trinomial.
Step1: Divide the equation by coefficient of
Step 2: Take the square of the half of the coefficient of x and add it to both sides of the equation.
Step 3: Factor the equation.
The standard form of the equation of the circle is
Calculation:
Consider the equation
Recall that in order to solve a quadratic equation, completing the square method is used that transforms the equation in the form of square trinomial.
Step1: Divide the equation by coefficient of
Step 2: Take the square of the half of the coefficient of x and add it to both sides of the equation.
Step 3: Factor the equation.
In the provided equation, add 4 to both the sides of the equation,
Next, add 25 to both the sides of the equation,
Group the terms,
Factor out the trinomial, recall that
Apply it,
Recall that the standard form of the equation of the circle is
Convert the equation obtained above in standard form,
Compare,
Here,
Therefore, center of circle is
Thus, the equation
Chapter 1 Solutions
EBK PRECALCULUS: MATHEMATICS FOR CALCUL
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning