Chapter 18.3, Problem 29PP

Interpretation Introduction

Interpretation:

$pHandpOH$ of given solution are to be calculated.

Concept introduction:

pH gives the concentration of hydrogen ion in a solution.

It tells about acidity and basicity of a solution.

It is given by:

$\begin{array}{l}pH=-\log \left[H^{+}\right]\\ pOH=-\log \left[O{H}^{-}\right]\\ pH+pOH=14\\ \left[H^{+}\right]isconcentationofhydrogenions\\ \left[O{H}^{-}\right]isconcentationofhydroxylions\end{array}$

Answer to Problem 29PP

$\begin{array}{l}pH=3.70\\ pOH=10.30\end{array}$

Explanation of Solution

HCl gives hydrogen ions in aqueous solution.

$\begin{array}{c}\left[H^{+}\right]=\frac{1\times {10}^{-3}}{5}\\ =2\times {10}^{-4}M\end{array}$

$pH=-\log \left[H^{+}\right]$

Therefore,

$\begin{array}{c}pH=-\log (2\times {10}^{-4})\\ =-\log 2-\log {10}^{-4}\\ =-0.30+4\\ =3.70\end{array}$

Therefore,

$\begin{array}{c}pOH=14-3.70\\ =10.30\end{array}$

Conclusion

Thus,

$\begin{array}{l}pH=3.70\\ pOH=10.30\end{array}$