Chapter 18, Problem 95A

Interpretation Introduction

Interpretation:

The volume of given $HCl$ solution is to be calculated when it is neutralized by base $KOH$.

Concept introduction:

Molarity is number of moles of solute present per liter of solution.

When acid and base are mixed, they neutralize each other. So their molar concentrations can be calculated by applying mole concept.

Answer to Problem 95A

Volume of $HCl$ is $475mL$

Explanation of Solution

Given data:

$\begin{array}{l}{m}_{KOH}=6g\\ MolarityofHCl=0.225M\end{array}$

Molar mass of $KOH=56g/mol$

$\begin{array}{c}{n}_{KOH}=\frac{6}{56}\\ =0.107mol\end{array}$

When $HCl$ reacts with $KOH$, reaction is given by:

$HCl+KOH\to KCl+H_{2}O$

Thus one mol acid reacts with one mol base.

This impies,

$n_{HCl}=0.107mol$

$\begin{array}{c}VolumeofHClsolution=\frac{0.107mol}{0.225M}\\ =0.475L\\ =475mL\end{array}$

Conclusion

$VolumeofHCl=475mL$