Chapter 18.1, Problem 1PP

(a)

Interpretation Introduction

Interpretation:

The reaction between aluminum and sulphuric acid is to be balanced.

Concept Introduction :

To balance a reaction, the number of atoms of each element on both sides should be equal.

Answer to Problem 1PP

$2\text{A}\text{l}+3{\text{H}}_2\text{S}{\text{O}}_4\to \text{A}{\text{l}}_2{\left(\text{S}{\text{O}}_4\right)}_3+3{\text{H}}_2$

Explanation of Solution

When aluminum reacts with sulphuric acid, aluminum sulfate and hydrogen are formed.

$\text{A}\text{l}+{\text{H}}_2\text{S}{\text{O}}_4\to \text{A}{\text{l}}_2{\left(\text{S}{\text{O}}_4\right)}_3+{\text{H}}_2$

Balancing the equation by making the number of each atom equal on both sides-

$2\text{A}\text{l}+3{\text{H}}_2\text{S}{\text{O}}_4\to \text{A}{\text{l}}_2{\left(\text{S}{\text{O}}_4\right)}_3+3{\text{H}}_2$

(b)

Interpretation Introduction

Interpretation:

The reaction between calcium carbonate and hydrobromic acid is to be balanced.

Concept Introduction :

To balance a reaction, the number of atoms of each element on both sides should be equal.

Answer to Problem 1PP

  $\text{C}\text{a}\text{C}{\text{O}}_3+2\text{H}\text{B}\text{r}\to \text{C}\text{a}\text{B}{\text{r}}_2+{\text{H}}_2\text{O}+\text{C}{\text{O}}_2$

Explanation of Solution

When calcium carbonate reacts with hydrobromic acid, calcium bromide, carbon dioxide and water are formed.

  $\text{C}\text{a}\text{C}{\text{O}}_3+\text{H}\text{B}\text{r}\to \text{C}\text{a}\text{B}{\text{r}}_2+{\text{H}}_2\text{O}+\text{C}{\text{O}}_2$

Balancing the equation by making the number of each atom equal on both sides-

  $\text{C}\text{a}\text{C}{\text{O}}_3+2\text{H}\text{B}\text{r}\to \text{C}\text{a}\text{B}{\text{r}}_2+{\text{H}}_2\text{O}+\text{C}{\text{O}}_2$