Chapter 18.3, Problem 25PP

Interpretation Introduction

(a)

Interpretation:

$pH$ of the solution is to be found out using given hydrogen ion concentration.

Concept introduction:

pH gives the concentration of hydrogen ion in a solution.

It tells about acidity and basicity of a solution.

It is given by:

$\begin{array}{l}pH=-\log \left[H^{+}\right]\\ \left[H^{+}\right]isconcentationofhydrogenions\end{array}$

Answer to Problem 25PP

pH of given solution is 2.26.

Explanation of Solution

Given:

$\left[H^{+}\right]=0.0055M$

$pH=-\log \left[H^{+}\right]$

Therefore,

$\begin{array}{c}pH=-\log (0.0055)\\ =-\log (5.5\times {10}^{-3})\\ =-\log 5.5-\log {10}^{-3}\\ =-0.74+3\\ =2.26\end{array}$

Interpretation Introduction

(a)

Interpretation:

$pH$ of the solution is to be found out using given hydrogen ion concentration.

Concept introduction:

pH gives the concentration of hydrogen ion in a solution.

It tells about acidity and basicity of a solution.

It is given by:

$\begin{array}{l}pH=-\log \left[H^{+}\right]\\ \left[H^{+}\right]isconcentationofhydrogenions\end{array}$

Answer to Problem 25PP

pH of given solution is 4.08.

Explanation of Solution

Given:

$\left[H^{+}\right]=0.000084M$

$pH=-\log \left[H^{+}\right]$

Therefore,

$\begin{array}{c}pH=-\log (0.000084)\\ =-\log (8.4\times {10}^{-5})\\ =-\log 8.4-\log {10}^{-5}\\ =-0.924+5\\ =4.08\end{array}$