Chapter 18, Problem 92A

Interpretation Introduction

Interpretation:

The Molarity of given acid solution is to be calculated when it is neutralized by base.

Concept introduction:

Molarity is number of moles of solute present per liter of solution.

When acid and base are mixed, they neutralize each other. So their molar concentrations can be calculated by applying mole concept.

Answer to Problem 92A

Molarity of lithium hydroxide is $0.2033M$

Explanation of Solution

Given data:

$\begin{array}{l}{V}_{LiOH}=25.00mL\\ MolarityofHCl=0.3340\text{}M\\ V_{HCl}=15.22mL\end{array}$

$\begin{array}{c}{n}_{HCl}=Molarity\times volumeinliters\\ =0.3340\times \frac{15.22}{1000}\\ =0.005083mol\end{array}$

When hydrochloric acid reacts with lithium hydroxide reaction is given by:

$HCl+LiOH\to LiCl+2H_{2}O$

Thus one mol acid reacts with one mol base.

This impies,

$n_{LiOH}=0.005083mol$

$\begin{array}{c}MolarityofLiOH=\frac{0.005083}{25/1000}\\ =0.2033M\end{array}$

Conclusion

$Molarity$ is $0.2033M$