
Concept explainers
(a)
Interpretation:
Whether the isomaltose is a monosaccharide, disaccharide or polysaccharide should be identified.
Concept Introduction:
Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is CnH2nOnwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
(b)
Interpretation:
To determine the monosaccharide unit present in isomlatose.
Concept Introduction:
Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is CnH2nOnwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
(c)
Interpretation:
The type of glycosidic linkage present in isomlatose should be determined.
Concept Introduction:
Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is CnH2nOnwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.
(d)
Interpretation:
To state the form of isomaltose in the given structure.
Concept Introduction:
Monosaccharides are most basic form of a carbohydrate and simplest form of sugars. They are unable to hydrolyze into simpler components and their general formula is CnH2nOnwhere n is the number of atoms of each of the elements present in a monosaccharide. A disaccharide is a type of sugar which is made up of two monosaccharides units that are joined together by a linkage known as glycosidic linkage. Glycosidic linkage is formed as a result of linkage of -OH group on carbon number1 of one monosaccharide with the hydroxyl group present on the carbon number 4 of other molecule of monosaccharide. The two monosaccharides forming disaccharide molecule can be same or different depending upon the disaccharide to be formed.

Want to see the full answer?
Check out a sample textbook solution
Chapter 18 Solutions
Basic Chemistry (5th Edition)
- CH, CH CH₂ CH₂ Phytyl side chain 5. What is the expected order of elution of compounds A-D below from a chromatography column packed with silica gel, eluting with hexane/ethyl acetate? C D OHarrow_forwardPlease analze my gel electrophoresis column of the VRK1 kinase (MW: 39.71 kDa). Attached is the following image for the order of column wells and my gel.arrow_forward2.0arrow_forward
- Write the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 5 6 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! ☐arrow_forwardCompare these chromatograms of three anti-psychotic drugs done by HPLC and SFC. Why is there the difference in separation time for SFC versus HPLC? Hint, use the Van Deemter plot as a guide in answering this question. Why, fundamentally, would you expect a faster separation for SFC than HPLC, in general?arrow_forwardA certain inorganic cation has an electrophoretic mobility of 5.27 x 10-4 cm2s-1V-1. The same ion has a diffusion coefficient of 9.5 x 10-6cm2s-1. If this ion is separated from cations by CZE with a 75cm capillary, what is the expected plate count, N, at an applied voltage of 15.0kV? Under these separation conditions, the electroosmotic flow rate was 0.85mm s-1 toward the cathode. If the detector was 50.0cm from the injection end of the capillary, how long would it take in minutes for the analyte cation to reach the detector after the field was applied?arrow_forward
- 2.arrow_forwardPlease solve for the following Electrochemistry that occursarrow_forwardCommercial bleach contains either chlorine or oxygen as an active ingredient. A commercial oxygenated bleach is much safer to handle and less likely to ruin your clothes. It is possible to determine the amount of active ingredient in an oxygenated bleach product by performing a redox titration. The balance reaction for such a titration is: 6H+ +5H2O2 +2MnO4- à 5O2 + 2Mn2+ + 8H2O If you performed the following procedure: “First, dilute the Seventh Generation Non-Chlorine Bleach by pipetting 10 mL of bleach in a 100 mL volumetric flask and filling the flask to the mark with distilled water. Next, pipet 10 mL of the diluted bleach solution into a 250 mL Erlenmeyer flask and add 20 mL of 1.0 M H2SO4 to the flask. This solution should be titrated with 0.0100 M KMnO4 solution.” It took 18.47mL of the KMnO4 to reach the endpoint on average. What was the concentration of H2O2 in the original bleach solution in weight % assuming the density of bleach is 1g/mL?arrow_forward
- 10.arrow_forwardProper care of pH electrodes: Why can you not store a pH electrode in distilled water? What must you instead store it in? Why?arrow_forwardWrite the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 569 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! §arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





