
Concept explainers
Interpretation:
To state the differences between the open-chain structure of D-galactose and D-glucose.
Concept introduction:
Monosaccharides are most basic form of a carbohydrate and simplest from of sugars. They are unable to hydrolyze into simpler components and their general formula is CnH2nOnwhere n is the number of atoms of each of the elements present in a monosaccharide. Glucose and galactose are one of the most important monosaccharides. Both of these fall in the category of hexose as they contain six carbon atoms in their structure and have the same molecular formula C6H12O6. Most common form of glucose and galactose which is found in nature is the D-isomer where -OH groups are present on the right of five carbon atoms present in the open chain structure. The only difference in their structure is the position of -OH group at carbon number 4 which can be seen in their structures.

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Chapter 18 Solutions
Basic Chemistry (5th Edition)
- When 2-bromo-93-dimethylbutane is heated with sodium methoxide, one majors.. në la formed. 4th attempt Part 1 (0.5 point) t Ji See Periodic Table See Hint Draw the major alkene product and all other byproducts. Be sure to include lone-pair electrons and charges. Part 2 (0.5 point) What type of mechanism is occuring? Choose one: AS1 3rd attempt X H 41 See Hint Part 1 (0.5 point) Feedback See Periodic Table See Hintarrow_forwardComplete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 2nd attempt 1 Provide the missing curved arrow notation. E+ RUDDA 1st attempt Feedback See Periodic Table See Hint Iir See Periodic Table See Hintarrow_forwardHeating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate base is a poor nucleophile. Further, heating the reaction mixture causes a greater increase in the rate of E1 compared to the rate of Sy1. 3rd attempt h Draw curved arrow(s) to show how the alcohol reacts with phosphoric acid. TH © 1 0 0 +1% # 2nd attempt Feedback H Ju See Periodic Table See Hint H Jud See Periodic Table See Hintarrow_forward
- Part 2 (0.5 point) 0- Draw the major organic product with the correct geometry. 10 1: 70000 х く 1st attempt Part 1 (0.5 point) Feedback Please draw all four bonds at chiral centers. P See Periodic Table See Hintarrow_forwardHeating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate base is a poor nucleophile. Further, heating the reaction mixture causes a greater increase in the rate of E1 compared to the rate of S№1. 2nd attempt 0 See Periodic Table See Hint Draw the organic intermediate from the first step (no byproducts) and draw curved arrow(s) to show how it reacts. TH +11: 1st attempt Feedback H H H C F F See Periodic Table See Hintarrow_forwardThis molecule undergoes an E1 mechanism when stirred in methanol. 3rd attempt CH₂OH CH₂OH 6148 O See Periodic Table. See Hint Draw 3 chemical species including formal charges and lone pairs of electrons. Add the missing curved arrow notation. H N O O SA 3 Br Iarrow_forward
- Complete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 1st attempt Y 0 + Provide the missing curved arrow notation. 01: See Periodic Table See Hint H C Br Iarrow_forwardPlease help answer number 2. Thanks in advance.arrow_forwardHow do I explain this? Thank you!arrow_forward
- When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 40 0 DEPT 135 T 200 160 120 80 40 0 Draw the unknown amide. Select Dow Templates More Fragearrow_forwardIdentify the unknown compound from its IR and proton NMR spectra. C4H6O: 'H NMR: 82.43 (1H, t, J = 2 Hz); 8 3.41 (3H, s); 8 4.10 (2H, d, J = 2 Hz) IR: 2125, 3300 cm¹ The C4H6O compound liberates a gas when treated with C2H5 MgBr. Draw the unknown compound. Select Draw с H Templates Morearrow_forwardPlease help with number 6 I got a negative number could that be right?arrow_forward
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