For the following system,
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Introductory Chemistry: An Active Learning Approach
- Write an equation for an equilibrium system that would lead to the following expressions (ac) for K. (a) K=(Pco)2 (PH2)5(PC2H6)(PH2O)2 (b) K=(PNH3)4 (PO2)5(PNO)4 (PH2O)6 (c) K=[ ClO3 ]2 [ Mn2+ ]2(Pcl2)[ MNO4 ]2 [ H+ ]4 ; liquid water is a productarrow_forwardAt a certain temperature, K=0.29 for the decomposition of two moles of iodine trichloride, ICl3(s), to chlorine and iodine gases. The partial pressure of chlorine gas at equilibrium is three times that of iodine gas. What are the partial pressures of iodine and chlorine at equilibrium?arrow_forwardShow that the complete chemical equation, the total ionic equation, and the net ionic equation for the reaction represented by the equation KI(aq)+I2(aq)KI3(aq) give the same expression for the reaction quotient. KI3 is composed of the ions K+ and I3-.arrow_forward
- Calculate the value of the equilibrium constant for the reaction N2(g)+2O2(g)2NO2(g) if the concentrations of the species at equilibrium are [N2] = 0.0013, [O2] = 0.0024, and [NO2] = 0.00065.arrow_forwardWrite the equilibrium constant expression, K, for the following reaction. Please enter the compounds in the order given in the reaction. If either the numerator or denominator is blank, please enter 1 HF (aq) + H20(1) H30+(aq) + F (aq) K =arrow_forwardWrite the equilibrium constant expression, K, for the following reaction taking place in dilute aqueous solution. (CH3)2NH (aq) + H2O(1) |(CH3),NH,* (aq) + OH'(aq) K =arrow_forward
- Write the equilibrium-constant expression for the reaction, NH3(aq) + H2O(l) ∆ NH4+(aq) + OH-(aq)arrow_forwardWrite the equilibrium constant expression, K, for the following reaction taking place in dilute aqueous solution.arrow_forwardWrite the equilibrium constant expression for this reaction: CH1,04(aq)+2 OH (aq) → 2 CH;COO (aq)+C,H¿O,(aq)arrow_forward
- Sulfur dioxide is a common preservative in wine; it prevents oxidation and bacterial growth. When SO2 is added to wine, it reacts with water to form an equilibrium system with the bisulfite ion: SO2(aq) + H2O(l) ↔↔H+(aq) + HSO3-(aq) In this equilibrium system, SO2, is called "molecular SO2"; in its HSO3- form it is called "free SO2". Only molecular SO2 acts like a preservative. The amount of molecular SO2 in the equilibrium system is highly pH dependent. The lower the pH, the more the equilibrium shifts to the left and the greater the amount of free SO2 is present. (it favors the reactants). The recommended amount of free SO2 is 0.8 ppm for white wine and 0.5 ppm for red wine. The table below shows the amount of free SO2 required to obtain the correct amount of molecular SO2 as a function of pH for both red and white wine. For dilute solutions such as these, 1 ppm = 1 mg/L. Using the table values, answer the following questions. Table: Amount of free SO2 required to maintain…arrow_forward(a) What does it mean when the reaction quotient, Q, is numerically equal to the equilibrium constant, Kc? (b) What does it mean when it is less than the equilibrium constant? (c) What does it mean when it is less than the equilibrium constant?arrow_forwardwrite the chemical reaction for the following equilibrium constantarrow_forward
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