
(a)
Interpretation: The following
Concept Introduction: In oxidation-reduction reaction, transfer of electron/s takes place. The transfer of electron, results in the formation of ions. In oxidation, loss of electron/s takes place and in reduction, gain of electron/s takes place.
(a)

Answer to Problem 47A
The balance oxidation-reduction reaction is-
Explanation of Solution
The oxidation state of each element in this reaction is calculated as follows:
Let oxidation state of Mn is x. Then, in
Oxidation state of O is
Oxidation state of Mn decreases from
Another element except O is balanced. Balance O by using
Oxidation state of O increases from
Balance H by adding
Multiply equation (1) by 2 and equation (2) by 5. After that, add both the equation to get the net balance equation.
In the overall reaction, charge and elements are balanced on both sides.
(b)
Interpretation: The following oxidation-reduction reaction needs to be balanced in acidic medium.
Concept Introduction: In oxidation-reduction reaction, transfer of electron/s takes place. The transfer of electron, results in the formation of ions. In oxidation, loss of electron/s takes place and in reduction, gain of electron/s takes place.
(b)

Answer to Problem 47A
The balance reduction- oxidation reaction is-
Explanation of Solution
The oxidation state of the each element in this reaction is given below:
Oxidation state of Br is
Oxidation state of Br decreases from
Other element except O is balanced. Balance O by using
Oxidation state of Cu increases from
Both elements are balanced. Now, add electrons to balance charge. To balance charge on both side add one electron to the right. Hence, the balanced equation is-
Multiply the equation (2) by 6. Add equation (1) and (2) to get the net balance equation.
In the overall reaction, charge and elements are balanced in both sides.
(c)
Interpretation: The following oxidation-reduction reaction needs to be balanced as an acidic medium.
Concept Introduction: In oxidation-reduction reaction, transfer of electron/s takes place. The transfer of electron, results in the formation of ions. In oxidation, loss of electron/s takes place and in reduction, gain of electron/s takes place.
(c)

Answer to Problem 47A
The balance oxidation-reduction reaction is-
Explanation of Solution
The oxidation state of the each element in this reaction is given below:
Oxidation state of N decreases from
Other element except O is balanced. Balance O by using
Oxidation state of
To balance I on both side, multiply reactant side I by to 2.
To balance charge on both side add
Multiply equation (1) by 2. After that, add both the equation to get the net balance equation.
In the overall reaction, charge and elements are balanced on both sides.
Chapter 18 Solutions
World of Chemistry
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