Chapter 18.1, Problem 4RQ

Interpretation Introduction

Interpretation: Oxidation state for two elements in the compound ${\text{OF}}_{\text{2}}$ needs to be stated.

Concept introduction: Oxidation state is the charge assigned to an atom in a compound. Oxidation-reduction reaction involves gain and loss of electrons from atoms.

Answer to Problem 4RQ

Oxidation state of fluorine is -1 and oxidation state of oxygen is +2.

Explanation of Solution

Given compound is ${\text{OF}}_{\text{2}}$ . In this compound, fluorine is more electronegative than oxygen. Thus, oxidation state of fluorine will be negative value (-1). ${\text{OF}}_{\text{2}}$ is an electrically neutral compound therefore sum of the oxidation state will be zero. Calculation of oxidation state of O represented as follows:

$\begin{array}{c}\text{x+2×}\left(-\text{1}\right)\text{=0}\\ \text{x=+2}\end{array}$

Conclusion

Thus, the oxidation state of O is +2 and oxidation state of F is -1.