DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 18, Problem 3CS
What types of engineering materials might be able to meet the requirements? What would be the pros and cons of each general family?
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Question 1
A three-blade propeller of a diameter of 2 m has an activity factor AF of 200 and its
ratio of static thrust coefficient to static torque coefficient is 10. The propeller's
integrated lift coefficient is 0.3.
(L=6847 mm, q = 5331 N/mm, M = 1408549 N.mm, and El = 8.6 x 1014 N. mm²)
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Chapter 18 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 18 - Briefly describe the evolution of forming...Ch. 18 - What are some of the possible means of classifying...Ch. 18 - How are bulk deformation processes different from...Ch. 18 - Prob. 4RQCh. 18 - Prob. 5RQCh. 18 - Prob. 6RQCh. 18 - Prob. 7RQCh. 18 - Why is it undesirable to minimize friction between...Ch. 18 - Prob. 9RQCh. 18 - Prob. 10RQ
Ch. 18 - Prob. 11RQCh. 18 - Prob. 12RQCh. 18 - Prob. 13RQCh. 18 - Prob. 14RQCh. 18 - Why is foil almost always rolled on a cluster...Ch. 18 - Prob. 16RQCh. 18 - Prob. 17RQCh. 18 - Prob. 18RQCh. 18 - Prob. 19RQCh. 18 - Explain how hot�rolled products can have...Ch. 18 - What is mill scale, and how can it be removed?Ch. 18 - Discuss the problems in producing uniform...Ch. 18 - Prob. 23RQCh. 18 - How might the addition of horizontal tensions act...Ch. 18 - What are some other techniques to reduce roll...Ch. 18 - What is thermomechanical processing, and what are...Ch. 18 - Provide a concise description of the forging...Ch. 18 - What are some of the types of flow that can occur...Ch. 18 - Prob. 29RQCh. 18 - Prob. 30RQCh. 18 - Prob. 31RQCh. 18 - Prob. 32RQCh. 18 - Prob. 33RQCh. 18 - Prob. 34RQCh. 18 - Prob. 35RQCh. 18 - Prob. 36RQCh. 18 - Prob. 37RQCh. 18 - Prob. 38RQCh. 18 - Prob. 39RQCh. 18 - Describe some of the primary differences among...Ch. 18 - What are some common examples of impression�die...Ch. 18 - What are some of the significant requirements of...Ch. 18 - Why are different tolerances usually applied to...Ch. 18 - What are some of the roles played by lubricants in...Ch. 18 - What are some of the attractive features of...Ch. 18 - What types of product geometry can be produced by...Ch. 18 - What is upset forging?Ch. 18 - What are some of the typical products produced by...Ch. 18 - What types of products can be produced by...Ch. 18 - What are some of the attractive features of...Ch. 18 - How does roll forging differ from a conventional...Ch. 18 - Describe the swaging process.Ch. 18 - What kind of products are produced by swaging?Ch. 18 - How can the swaging process impart different sizes...Ch. 18 - What are some possible objectives of...Ch. 18 - Provide a concise definition of extrusion.Ch. 18 - What metals can be shaped by extrusion?Ch. 18 - What are some of the attractive features of the...Ch. 18 - What is the primary shape limitation of the...Ch. 18 - What is the primary benefit of indirect extrusion?Ch. 18 - What are some temperature considerations in hot...Ch. 18 - Why might lubricant selection be more critical in...Ch. 18 - What are some possible causes of surface cracks in...Ch. 18 - How might tubular products be made by extrusion?Ch. 18 - What types of products are made using a...Ch. 18 - Why can lubricants not be used in spider�mandrel...Ch. 18 - What are some of the attractive features of...Ch. 18 - What are some unique concerns and limitations of...Ch. 18 - What is the unique capability provided by...Ch. 18 - How is the feedstock pushed through the die in...Ch. 18 - Describe the Conform process of continuous...Ch. 18 - What types of feedstock can be used in continuous...Ch. 18 - How is wire, rod, and tube drawing different from...Ch. 18 - Why are rods generally drawn on draw benches,...Ch. 18 - Why is the reduction in area significantly...Ch. 18 - What is the difference between tube drawing and...Ch. 18 - For what types of products might a floating plug...Ch. 18 - What are some of the benefits of cold drawing of...Ch. 18 - What types of materials are used for...Ch. 18 - What is the benefit of a tandem wire drawing...Ch. 18 - What is cold forming?Ch. 18 - What types of products are produced by cold...Ch. 18 - What is impact extrusion and what variations...Ch. 18 - If a product contains a large�diameter head and...Ch. 18 - What are some of the attractive properties or...Ch. 18 - What process can be used to produce seamless pipe...Ch. 18 - What type of products can be made by the...Ch. 18 - What types of rivets can be used when there is...Ch. 18 - How is coining different from a process known as...Ch. 18 - Why might hubbing be an attractive way to produce...Ch. 18 - How might a peening operation increase the...Ch. 18 - What is burnishing?Ch. 18 - Prob. 1PCh. 18 - Consider the extrusion of a cylindrical billet,...Ch. 18 - The force required to compress a cylindrical solid...Ch. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - Prob. 7PCh. 18 - Prob. 8PCh. 18 - Based on the size, shape, and desired precision,...Ch. 18 - What types of engineering materials might be able...Ch. 18 - For each of the shape generation methods in part...Ch. 18 - Which of the combinations of part 4 do you feel...Ch. 18 - For this system, outline the specific steps that...Ch. 18 - For your proposed solution, would any additional...
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- Calculate the maximum shear stress Tmax at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places. Select one: ○ 1.2681.818 O 2. 25745.455 O 3. 17163.636 O 4. 10727.273 ○ 5.5363.636arrow_forwardIf L-719.01 mm, = 7839.63 N/m³, the normal stress σ caused by self-weight at the location of the maximum normal stress in the bar can be calculated as (Please select the correct value of σ given in Pa and rounded to three decimal places.) Select one: ○ 1. 1409.193 2. 845.516 O 3. 11273.545 ○ 4.8455.159 ○ 5.4509.418 6. 2818.386 7.5636.772arrow_forwardTo calculate the rotation at Point B, a suitable virtual structure needs to be created. Which equation in the following choices most accurately represents the functional relationship between the bending moment, Mv2 ( Units: N.mm), of the virtual structure and the spatial coordinate x (Units: mm) if the applied unit virtual moment is clockwise? Select one: O 1. Mv2 1.000 O 2. Mv2=x+1.000 O 3. Mv2=x+0.000 4. Mv2 = -x-1.000 O 5. Mv2 -1.000 6. Mv2=-x+0.000arrow_forward
- The vertical deflection at Point B can be calculated as ( The following choices are provided in units of mm and rounded to three decimal places ; the downward deflection is negative and upward deflection is positive. ) Select one: 1. 1703.065 2. -1703.065 3. -2043.679 4.1362.452 5. -1362.452 6. 2043.679arrow_forwardThe second moments of area about z-axis, /z, and the second moments of area about y-axis, ly, can be calculated as Select one: O 1. I = Iz ○ 2. Ly ○ 3. ○ 4. ○ 5. = = Iz = *D' 64 I₁ = D, Iz Ly Ly = 32 *D' = = 3 Iz = *D' 32 = *D' O 6. Iy=D, Ly = D², Iz = 32 O 7. Ly = Iz D = 64 32arrow_forward[If L=3508 mm, W-9189 N, E=80 GPa, Determine the deflection at the free end of the beam.] Step -2 Which equation in the following choices most accurately represents the functional relationship between the value of the slope O (Units: Radian) at half length (x = L/2) of the beam and the second moment of area about z-axis, Izz (Units: mm²), of the cross section? (Please note that " X = L/2" is the same as "X = L ÷ 2" .) Select one: O 1.0 448787.925/Izz O 2.0 279167.292/Izz O 3.0 38871.395/Izz O 4.0 114847.304/Izz O 5.0 176688.160/Izz O 6.0 609574.150/Izz O 7.0 70675.264/Izzarrow_forward
- Use the principle of virtual work to determine the vertical deflection and rotation at tip (Point B) of the cantilever shown below. (L=6847 mm, q = 5331 N/mm, M = 1408549 N.mm, and El = 8.6 x 1014 N. mm²) q Y M X A ΕΙ B L Step -1 Let the coordinates defined with origin located at B and x-axis pointing to the Left and Y-axis pointing upward. The bending moment, M (Units: N.mm), in the beam as a function of spatial coordinate x(Units: mm) can be most accurately described by Select one: 1. M=1126839.200 +2132.400*x*x 2. M=-1408549.000 - 3198.600*x*x 3. M=-1408549.000-2665.500*x*x 4. M=-1408549.000-2132.400*x*x 5. M= -1408549.000+2665.500*x*x 6. M= 1408549.000 + 2665.500*x*x 7. M= 1408549.000-2665.500*x*xarrow_forwardCalculate the principal stress σ at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places Select one: O 1.5363.64 O 2. 12872.727 3.9118.182 4. 10727.273 5. 16090.909 6. 2681.818arrow_forwardQuestion2 The mission profile for a jet driven aircraft consists of the following segments: engine start and warm-up, taxi, take-off, climb to the cruise altitude of 35000 ft, descend to 10000 ft, one hour loiter at this altitude at 60% of the cruise speed, flight at loiter speed and altitude to an alternate airport (100 nm), descend to landing approach condition followed by the final landing, taxi and shutdown. The cruise Mach number is 0.8. No provisions are made for the reserved fuel or any trapped oil and fuel. The aircraft carries 200 people (including pilots and the cabin crew) at 175 lb each and 90 lb baggage each. This aircraft has a wing area of 2000 ft² L/D at cruise L/D at 10000ft flight Table Q2 20 16 0.43 lb/hr/lb 0.50 lb/hr/lb C: Specific Fuel Consumption at cruise: C: Specific Fuel Consumption at 10000 ft flight: Weight ratios Engine Start and warm-up Taxi Take-off Climb Descent Landing, taxi and shutdown 0.992 0.996 0.996 0.996 0.992 0.992 Question 2 continues on the…arrow_forward
- Calculate the principal stress σ1_at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places. Select one: O 1.25745.455 O 2. 32181.818 3. 21454.545 4. 17163.636 5. 12872.727arrow_forwardCalculate the Von-Mises effective stress at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places Select one: O 1.27870.272 O2. 18580.181 3. 11148.109 O 4. 14864.145 O 5.22296.218arrow_forwardA bar of length L and of a circular cross-section of diameter D is clamped at the top end and loaded at the other (bottom) end by a point load P as shown in Figure Q2a. The cross-section of the bar is shown in Figure Q2b indicating that load is applied at the point A. The material used in the bar has specific weight y. Find the magnitude and location of the maximum normal stress in the bar. Figure Q2 a Figure Q2 b 45°arrow_forward
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