A close end tube of thin-walled circular section may be subjected to torque 7 and internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²t), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>>t, you can approximately assume that the internal radius of the tube is equal to Rin the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T Ozz Gee Orr Z бее Ozz Figure Q3 R Centreline of the wall Calculate the principal stress σ at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places Select one: O 1.5363.64 O 2. 12872.727 3.9118.182 4. 10727.273 5. 16090.909 6. 2681.818
A close end tube of thin-walled circular section may be subjected to torque 7 and internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by the torque can be calculated as T = T/(2πR²t), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>>t, you can approximately assume that the internal radius of the tube is equal to Rin the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v. Orr T Ozz Gee Orr Z бее Ozz Figure Q3 R Centreline of the wall Calculate the principal stress σ at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m. The following choices are provided in units of MPa and rounded to three decimal places Select one: O 1.5363.64 O 2. 12872.727 3.9118.182 4. 10727.273 5. 16090.909 6. 2681.818
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A close end tube of thin-walled circular section may be subjected to torque 7 and internal pressure P, as shown in Figure Q3. The shear stress in the wall caused by
the torque can be calculated as T = T/(2πR²t), where the mean radius of the cross section is R (i.e., the radius of the centreline of the wall) and the wall thickness
is t. The internal radius of the tube can be calculated as (R-t/2). However, as R>>t, you can approximately assume that the internal radius of the tube is equal to Rin
the subsequent calculation. The tube is made from a material with Young's modulus E, Poisson's ratio v.
Orr
T
Ozz
Gee
Orr
Z
бее
Ozz
Figure Q3
R
Centreline of
the wall

Transcribed Image Text:Calculate the principal stress σ at the selected element within the wall (Fig. Q3) if T = 26.7 KN.m, P = 23.6 MPa, t = 2.2 mm, R = 2 m.
The following choices are provided in units of MPa and rounded to three decimal places
Select one:
O 1.5363.64
O 2. 12872.727
3.9118.182
4. 10727.273
5. 16090.909
6. 2681.818
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