Determine the internal normal, shear, and bending moment at "C" which is just to the right of the 6 kN load. (ANS: Nc = 0, Vc = 1 kN, Mc = 15 kNm) 6 kN A B C 3 m- 6 m 9 kN·m D
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- Draw the Free Body Diagram, Shear Force Diagram, and Bending moment Diagram for this please!Solve the problem in the picture and draw a FBD of section CD3 For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. V = 9 kN, V2 = 9 kN, V3 = 200 mm, and V4 = 1100 mm. ATAT-V3 Provide values at all key points shown in the given shear-force and bending-moment diagrams. X (mm) B A = B = C = D = E= F= P = Q = E * KN * KN * KN × KN KN x KN ✩ kN.mm *kN.mm D 0.00 Reaction force R₁ (left) = In the shear-force and bending-moment diagrams given, +V 0.00 X (mm) 6.3 kN and reaction force R2 (right) = P 11.7 kN. Q 0.00
- i need the answer quicklyConsider the beam in (Figure 1). Take that M = 32 kN-m and P = 12 kN. Determine the normal force, shear force, and moment at point C. Follow the sign convention. igure M A с 1.5 m 1.5 m-1.5 m-1.5 m- B 1 of 1 ▼ Part A Determine the normal force at point C. Express your answer to three significant figures and include the appropriate units. No = Submit Part B Submit Part C ■μÀ HA Value Vc = Value Mc = Determine the shear force at point C. Express your answer to three significant figures and include the appropriate units. Submit Request Answer | MA 3 Request Answer HA Value Units Determine the moment at point C. Express your answer to three significant figures and include the appropriate units. Roquoot Anouor Units www. ? B Units ? ?The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A
- Problem Statement Based on Problem 7-14 from the textbook. Determine the normal force, shear force, and moment at points F and E. w=60 lbs/ft a= 5 ft b=5.5 ft A -3 ft E 12 ft B a b 2 ftConsider the two-member frame shown in (Figure 1). Suppose that w1 = 250 N/m , w2 = 420 N/m . Follow the sign convention. Determine the internal normal force at point E. Determine the internal shear force at point E. Determine the internal moment at point E.Find the second moment of area, the location of the neutral axis, and the distances from the neutral axis to the top and bottom surfaces. Consider that the section is transmitting a positive bending moment about the z axis, Mz, where M₂ = 10 kip-in if the dimensions of the section are given in ips units, or M₂ = 1.13 kN·m if the dimensions are in Sl units. Determine the resulting stresses at the top and bottom surfaces and at every abrupt change in the cross section. From the figure, с - 12.5 B A y I 50 100 75 12.5- 12.5 25 D 100 The area is determined to be 3750 mm² The distances from the neutral axis to the top and bottom surfaces are determined to be 57.292 The second moment of area is determined to be 4.293 x 106 mm4. mm and 42.708 ✪ mm.
- Find the second moment of area, the location of the neutral axis, and the distances from the neutral axis to the top and bottom surfaces. Consider that the section is transmitting a positive bending moment about the z axis, Mz, where M₂ = 10 kip-in if the dimensions of the section are given in ips units, or M₂ = 1.13 kN·m if the dimensions are in Sl units. Determine the resulting stresses at the top and bottom surfaces and at every abrupt change in the cross section. From the figure Z 1 in 112 in y in → ← ¹ in 12 in D C B A ++ in The area is determined to be 2.0625 in². The distances from the neutral axis to the top and bottom surfaces are determined to be 0.858 x in and The second moment of area is determined to be 0.447 in 4. 1.017 xin.18KN/M D 3m 5m 1-25 m EL = Constant B Draw Bending Moment diagram after you analyze the structure using the force Method. Redundant: vertical reaction and moment at B.Only handwitten answer is needed