Concept explainers
(a)
Interpretation: The reason as to why electrophilic substitution occurs on the ring without
Concept introduction: The substitution reaction involves the replacement of one
(b)
Interpretation: The reason as to why electrophilic substitution occurs more readily at
Concept introduction: The substitution reaction involves the replacement of one functional group by other functional group. In nucleophilic substitution an electron rich species attack the species that is deficient in electrons. The electrophile and the leaving group together form a substrate. The nucleophile attacks over the substrate and there occurs the removal of leaving group from the substrate.
(c)
Interpretation: The reason as to why electrophilic substitution occurs more readily at
Concept introduction: The substitution reaction involves the replacement of one functional group by other functional group. In nucleophilic substitution an electron rich species attack the species that is deficient in electrons. The electrophile and the leaving group together form a substrate. The nucleophile attacks over the substrate and there occurs the removal of leaving group from the substrate.
Want to see the full answer?
Check out a sample textbook solutionChapter 18 Solutions
Organic Chemistry-Package(Custom)
- Consider the tetracyclic compound with rings labeled A–D. (a) Which ring is the most reactive in electrophilic aromatic substitution? (b) Which ring is the least reactive in electrophilic aromatic substitution?arrow_forward(a) Draw the products (including stereoisomers) formed when 2methylhex-2-ene is treated with HBr in the presence of peroxides. (b) Draw the products (including stereoisomers) formed when (S)-2,4dimethylhex-2-ene is treated with HBr and peroxides under similar conditions.arrow_forwardConsider the tetracyclic aromatic compound drawn below, with rings labeled as A, B, C, and D. (a) Which of the four rings is most reactive in electrophilic aromatic substitution? (b) Which of the four rings is least reactive in electrophilic aromatic substitution? (c) What are the major product(s) formed when this compound is treated with one equivalent of Br2?arrow_forward
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenyl-1-propanol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates-the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon. H Br он H20 1-bromo-1-phenylpropane 1-phenyl-1-propanol observed [a) = +5.0 optically pure S isomer, [a] =-48 %3Darrow_forwardAcyclovir is an effective antiviral agent used to treat the herpes simplexvirus. (a) Draw the enol form of acyclovir, and explain why it is aromatic.(b) Why is acyclovir typically drawn in its keto form, despite the fact thatits enol is aromatic?arrow_forwardKk.58.arrow_forward
- Methotrexate, a drug that inhibits the metabolism of folic acid, is used in the treatment of a variety of cancers and autoimmune disorders such as rheumatoid arthritis. (a) GIve the hybridization of each N atom in methotrexate. (b) In what type of orbital does the lone pair of each N reside? (c) Explain why the bicyclic ring system that contains four N atoms is aromatic.arrow_forwardResveratrol is an antioxidant found in the skin of red grapes. Its anticancer, anti-inflammatory, and various cardiovascular effects are under active investigation. (a) Draw all resonance structures for the radical that results from homolysis of the OH bond shown in red. (b) Explain why homolysis of this OH bond is preferred to homolysis of either OH bond in the other benzene ring.arrow_forward(a) Give an acceptable name for compound A. (b) Draw the organic products formed when A is treated with each reagent: [1] H3O+; [2] −OH, H2O; [3] CH3CH2CH2MgBr (excess), then H2O; [4] LiAlH4, then H2O.arrow_forward
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forward(a) What is the major alkene formed when A is dehydrated with HS2O4? (b) What is the major alkene formed when A is treated with POCl3 and pyridine? Explain why the major product is different in these reactions.arrow_forward(a) Why are alkyl halides insoluble in water? (b) Why is Butan-l-ol optically inactive but Butan-2-ol is optically active? (c) Although chlorine is an electron withdrawing group, yet it is ortho-, Para- directing in electrophilic aromatic substitution reaction. Why?arrow_forward