Explanation Given: Design 1 is thin walled pipe. Thin walled pipe is at rest at t = 0 . Concept used: Expression for newton’s second law of motion in translation is given as follows: ∑ F n e t = m a ...... (1) Here,net vertical force is ∑ F n e t and mass of walled pipe is m . Expression for newton’s second law of motion in rotation is given as follows: ∑ T n e t = I α ...... (2) Here, net torque on the system is ∑ T n e t , mass moment of inertia is I and angular acceleration of the system is α . Calculation: Free body diagram for the system is given as follows: Substitute m g − T for ∑ F n e t in equation (1). m g − T = m a Substitute T × r for ∑ T n e t in equation (1) To determine (b) The Velocity of the center of design 2.

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ISBN: 9781259977237

Author: BEER

Publisher: MCG

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Chapter 17.2, Problem 17.71P

To determine

(a)

TheVelocity of the center of design 1.

To determine

(b)

The Velocity of the center of design 2.

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Chapter 17.2, Problem 17.70P

Chapter 17.2, Problem 17.72P

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(a) TheVelocity of the center of design 1.

Solution Summary: The author explains how the velocity of the center of design 1 is gt2.